Principles of Foundation Engineering, SI Edition
8th Edition
ISBN: 9781305446298
Author: Braja M. Das
Publisher: Cengage Learning US
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Chapter 5, Problem 5.13P
To determine
Find the gross ultimate bearing capacity of the foundation.
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Given below is an earth retaining structure. The friction between the base and the soil below is 40°.
Through geotechnical investigation it was found that the soil on-site had an ultimate bearing
capacity of 360 kPa. Use unit weight of concrete = 24 kN/m³.
Y= 15 kN/m³
9 = 27°
c = 0 kPa
2 m
3.5 m
y = 16.5 kN/m³
9 = 35°
c = 10 kPa
Y= 13 kN/m³
9 = 11°
c = 21 kPa
1.2 m
0.6 m
1.5 m
0.6 m
3 m
a) What is the factor of safety against sliding?
b) What is the factor of safety against overturning?
c) What is the factor of safety against bearing capacity?
A square column foundation is to be
constructed on a sand deposit (C = 0). The
allowable load Q will be inclined at an angle b
Ø = 20° with the vertical. Knowing that y =
16.5 KN/ m3 and Df = 1 m. The standard
Penetration numbers N60 obtained from the
field are as follows. Determine value of Q ?
Depth (m)
N60
1.5
3
3.0
6
4.5
6.0
10
7.5
10
B- 1.25 m-
Select one:
a. 110 KN
O b. 151.7 KN
c. 95 KN
d. 155.3 KN
A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.
Chapter 5 Solutions
Principles of Foundation Engineering, SI Edition
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- For the design of an eccentrically loaded shallow foundation, given the following: Y = 19 kN/m³ Ysat = 20 kN/m³ p' = 30° C' = 8 kN/m² Water Table at 0.5 m depth from GL Soil: 3 Foundation: Size = 1.5 m * 1.5 m Df = 1 m from GL e/B = 0.10 (one way eccentricity) Estimate the ultimate load per unit length of the foundation. using Meyerhof's methodarrow_forwardA square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of Fqd ? Depth (m) W60 1.5 3 3.0 16 4.5 6.0 10 7.5 10 B- 1.25 m- Select one: a. 1.162 b. 11.62 c. 1.231 O d. 31.12arrow_forward10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3 could be useful. Determine the increase in vertical stress, in kPa, Aoz at a depth of z=3m under point F. B 4m 3m 6m E 10m Table 10.3 Variation of I, with m and n m 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 0.1 0.0047 0.0092 0.0270 0.0279 0.2 0.0132 0.0092 0.0179 0.0259 0.0132 0.0259 0.0374 0.0222 0.0242 0.0435 0.0474 0.0629 0.0686 0.0258 0.0504 0.0528 0.0547 0.3 0.0731 0.0766 0.0794 0.4 0.1013 0.5 0.0198 0.0387 0.1202 0.6 0.0222 0.0435 0.7 0.0242 0.0474 0.0947 0.1069 0.1168 0.1247 0.1311 0.1361 0.1365 0.1436 0.1491 0.1537 0.1598 0.0168 0.0198 0.0328 0.0387 0.0474 0.0559 0.0168 0.0328 0.0474 0.0602 0.0711 0.0801 0.0873 0.0931 0.0977 0.0559 0.0711 0.0840 0.0947 0.1034 0.1104 0.1158 0.0629 0.0801 0.0686 0.0873 0.1034 0.8 0.0258 0.0504 0.0731 0.0931 0.1104 0.9 0.0270 0.0528 0.0766 0.0977 0.1158 0.0794 0.1013 0.1202 0.0832 0.1263 1.4 0.1300 1.6 0.0306 0.0599 0.0871 0.1114 0.1324 1.8 0.0309 0.0606…arrow_forward
- A square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of qu ? Depth (m) N60 1.5 3 3.0 4.5 6.0 10 7.5 10 B 1.25 m Select one: a 273 66 KN/ m²arrow_forwardThe longitudinal foundation is located on the ground as shown in Figure 1. The foundation is located on the ground with 2 layers of soil. Soil data as follows: a. land 1: y1 = 19 kN/m3, c1 = 20 kN/m2 , p1 = 25° b. land 2: y2 = 19,5 kN/m3. c2 = 50 kN/m2 , Q2 = 30° If the depth of the foundation is 1 m, the width of the foundation is 2 m and a general shear failure is considered, determine the maximum allowable foundation load based on the Terzaghi bearing capacity formula, with a safety factor of 3! Layer 1 Layer 2 Figure 1arrow_forwardA column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, o' = 25°, c' = 50 kN/m². Using Eq. (3.23) and FS = 4, determine the net allowable load [see Eq. (3.15)] the foundation could carry. Use bearing capac- ity, shape, and depth factors given in Şection 3.6.arrow_forward
- A continuous foundation is shown. If the load eccentricity is 0.2m, determine the ultimate load, Qu, per unit length of foundation using Meyerhoff's Method. Sand 1.5 m $' = 40° c'=0 Y = 16.5 kN/m³ Select the correct response: 3584.32 4681.37 6813.52 5261.36 2 marrow_forwardRefer to Figure 5.9. For a continuous foundation in two-layered clay, given:●● γ1 = 121 lb/ft3, cu(1) = 1000 lb/ft2, Φ1 = 0●● γ2 = 115 lb/ft3, cu(2) = 585 lb/ft2, Φ2 = 0●● B = 3 ft, Df = 1.65 ft, H = 1.65 ftFind the gross allowable bearing capacity. Use a factor of safety of 3.arrow_forwardA column foundation is 3 m × 2 m in plan. Given: Dƒ = 1.5 m, þ' = 30°, c′ = 80 kN/m². Using the general bearing capacity equation (CFEM see class slides from March 17 similar to Example 1 and 2 but with an added capacity term related to cohesion) and 0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, Ną, and Ny directly from the table on page 26 of the lecture slides use the highlighted columns. Also, determine the maximum factored load for the column. - 1.5 m ↑ 1 m 3m x 2m - y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³ =arrow_forward
- For a shallow foundation shown below: Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eg and eL is 0.33 m and 0.12 m, respectively. G.S Iz 2 m (2 m x 3 m) Silty clay Yd=17 kN/m³ , Ysat = 20 kN/m³ %3D 6 m c'=78 kN/m? þ'=35° Shear modulus=250 kN/m? CS Scanned with CamScannerarrow_forwardProblem 2: A rectangular foundation of 4m × 6m (as shown in Figure P2) transmits a stress of 150 kPa on the surface of a soil deposit. Plot the distribution of induced vertical stresses with depth under points A (the centre of the rectangle), B and C up to a depth of 20 m. 6m 4m A Figure P2 B 2m с 2marrow_forward1. For the following cases, determine the allowable gross vertical load bearing capacity of the foundation. Use Terzaghi's equation. Part В D; Foundation Type 3 ft 3 ft 28° 400 psf 110 pcf Continuous a b 1.5 m 1.2 m 35° 17.8 kN/m³ Continuous 3 m 30° 30° 16.5 kN/m³ Square 2. A square foundation has to carry gross allowable load of 1805 kN (FS=3). Given: D; = 1.5 m, y=15.9 kN/m³, 0=34°, and c = 0. Use Terzaghi's equation to determine the size of the foundation (B).arrow_forward
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