Concept explainers
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:
Volume of bucket =
Weight of empty bucket = 20.3 lb
Weight of bucket filled with dry rodded coarse aggregate:
Trial 1 = 76.6 lb
Trial 2 = 75.1 lb
Trial 3 = 78.8 lb
a. Calculate the average dry-rodded unit weight
b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
Materials for Civil and Construction Engineers (4th Edition)
Additional Engineering Textbook Solutions
Elementary Surveying: An Introduction To Geomatics (15th Edition)
Foundation Design: Principles and Practices (3rd Edition)
Elementary Surveying (14th Edition)
Structural Steel Design (6th Edition)
Structural Analysis (10th Edition)
Engineering Mechanics: Statics
- 1. In the bulk unit weight experiment why should the aggregate be placed in layers and then rodded instead of filling up the container and then rodding it. 2. In a straight portion of a river which between gravel or sand will accumulate on the upstreamand which will accumulate on the downstream. Explain whyarrow_forwardDetermine Admixtures in ml/m3 Fine aggregate requirements (dry), in kg/m3 Net Water Content, in kg/m3arrow_forwardAn aggregate sample has a compacted dry unit weight of 1615 kg/m3 and a dry specific gravity of 2.15 If this aggregate is placed in a container and compacted with the same procedure used in the determination of compacted unit weight, what will be the amount of pores, in percent of the container volume, between the aggregate particles? (density of water = 1000 kg/m3)arrow_forward
- determine the effective specific gravity of aggregates. DATA: Specific Gravity: Fine Agg = 2.603 Coarse Agg = 2.740 Asphalt Cement = 1.048 Percent By Weight: Fine Agg = 47.90 Coarse Agg= 47.78 Asphalt Cement= 100-FA-CAarrow_forwardCoarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kg Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.arrow_forwardStrength requirements, in MPa – 30.68 Mpa Water cement ratio, in decimal – 0.45 Coarse aggregate requirements (dry), in kg/m3 – 992.kg/m3 Air content, in percent – 3.5% Water content, kg/m3 – 184 kg/m3 Cement, in kg/m3 – 408.89 kg/m3 Determine the Admixtures in ml/m3 Fine aggregate requirements (dry), in kg/m3 Net Water Content, in kg/m3arrow_forward
- Choose one answer 1.target mean strength fm (mpa) 1. 28.12 2. 33.12 3. 40.12 4. 25.12 2.w/c ratio 1. 0.58 2. 0.61 3. 0.51 4. 0.48 3 .the free water content is (kg/m3) 1. 180 2. 205 3. 190 4 .160 4.total aggregate content is (kg/m3) 1. 1889.7 2. 1869.7 3. 1899.7 4. 1879.7 5.the coarse aggregate is (kg.m3) 1. 1150.51 2. 1170.51 3. 1130.51 4. 1190.51arrow_forwardchoose true or false If you know that weights of coarse aggregate as follow :Weight of aggregate stock = 5350 gm, weight of aggregate in oven dry= 5200 gm, weight of aggregate submerged in water =3254 gm, weight of aggregate SSD= 5220 gm , According to weights above , the oven dry bulk specific gravity is 2.325arrow_forwardSuppose you had 10 kg (10000 g) sample of an aggregate at air dry conditions (Moisture Content = 0.07%). How much water (in grams) would be needed to bring the sample to SSD conditions? Show work.arrow_forward
- "A sieve analysis test was performed on a sample of fine aggregate and produced the following results:Sieve, mm 4.75 2.36 2.00 1.18 0.60 0.30 0.15 0.075 pan.Amount retained, g 0 33.2 56.9 83.1 151.4 40.4 72.0 58.3 15.6 .Calculate the percent passing each sieve, and draw a 0.45 power gradation chart with the use of a spreadsheet program. The specific steps or functions selected in the following description can vary somewhat depending on the version of the spreadsheet program being used.Calculate the fineness modulus of the sieve analysis results of Sample Problemarrow_forwardVoid Content—Calculate the void content in the aggregate using the bulk densitydetermined by either the rodding, jigging or shoveling procedure, as follows:arrow_forwardCalculate the percent voids between aggregate particles that have been compacted by rodding, if the dry-rodded unit weight is 88.0 lb/cu ft and the bulk dry specific gravity is 2.701.arrow_forward
- Structural Analysis (10th Edition)Civil EngineeringISBN:9780134610672Author:Russell C. HibbelerPublisher:PEARSONPrinciples of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781337705028Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
- Fundamentals of Structural AnalysisCivil EngineeringISBN:9780073398006Author:Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel LanningPublisher:McGraw-Hill EducationTraffic and Highway EngineeringCivil EngineeringISBN:9781305156241Author:Garber, Nicholas J.Publisher:Cengage Learning