WATER RESOURCES ENGINEERING (CL)
3rd Edition
ISBN: 9781119625827
Author: Mays
Publisher: WILEY
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Chapter 5, Problem 5.2.1P
To determine
The critical depth for culvert.
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Chapter 5 Solutions
WATER RESOURCES ENGINEERING (CL)
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- An elliptical culvert is 3.5 feet tall and 9 feet wide. It is filled with water to a depth of 1.05 feet. Find width of the stream.arrow_forwardQuestion 11 of 23 A discharge of 1.2 m3/s flows on an open channel with a slope of 0.0062. If the coefficient of roughness is 0.0123, compute the depth of the channel for an optimum discharge for a triangular section. Select the correct response: 0.49 m 0.41 m 0.51 m 0.69 m < Previous Continuoarrow_forwardQ3/ determine the discharge in the compound open channel shown in figure assume a bed slope (0.001) and the Manning coefficient is 0.03. * flood plain main channel flood plain 0.2m 10m 0.5m 10m 5marrow_forward
- A rectangular channel section increases in width from 40 ft to 50 ft in a length of 100 ft. The channel slope is 0.1%. If the discharge and the velocity of flow at section 1 are 2950 cfs and 12.8 ft/sec, respectively, determine the depths of flow at sections 1 and 2 and the velocity at section 2. Use the energy principle. Disregard the losses.please show step by step.arrow_forwardIn a rectangular channel 2.5 feet wide with a discharge of 15 cfs and upstream depth of 6 inches, there is a 9 inch riser. What is the depth of flow after the riser? Why does the depth fall or rise? Note: kindly give me right solution according to the questionarrow_forwardA discharge of 1.90 m3/s flows on an open channel with a slope of 0.0062. If the coefficient of roughness is 0.012, compute the depth (in m) of the channel for optimum discharge using: A. semi-circular section Choices: 1.36 0.63 1.63 0.36 B. Rectangular section Choices: 1.58 1.85 0.85 0.58 C. Triangular section Choices: 0.28 0.82 1.28 1.82 Note: please base your answer on the given choices thank you and also this is a complete questions thank youarrow_forward
- A rectangular channel (b = 9 feet) crosses beneath a roadway inside a 70-inch RCP culvert with a C = 0.6. Note: That the culvert dimensions may not be a standard size. 1. If the design flow rate is 281 cfs what is the water surface elevation when the invert elevation of the pipe is 1,277 ft. Report to 1 decimal place 2. Provide a profile view of the channel entering the culvert. Include the invert elevation, diameter, headwater and water surface elevation on your scratch paper.arrow_forwardA concrete-lined trapezoidal channel has to be constructed to carry a discharge of 500 cfs. Design the channel. Assume that the following values were fixed based on the site conditions: • Bed slope = 0.002 • n = 0.015 • Side slope, z = 1 (vertical):1.5 (horizontal) • b/y ratio = 2.0arrow_forwardA uniform flow occurs in a 4.3m diameter circular concrete culvert, but the depth changes depending on the weather (due to storms). The Manning coefficient is n = 0.014, and the channel slope is So = 0.0004. What is the discharge in m3/s when the depth of flow is 3.3m?arrow_forward
- 2. Flow occurs through a sand-filled pipe with a cross- sectional area of 60 cm?. If K is 10 cm/s and the gradient is 0.01, what is the discharge from the pipe?arrow_forward(c) A mountain creek with a flow rate of 100 ft/s passes through an eight-ft diameter circular culvert laid at a bottom slope of 1 ft./mile. Determine the critical depth of flow in the culvert. [2]: Provide two examples of each of the non-uniform and unsteady flows in open channels.arrow_forward1. Determine the discharge rate through three parallel corrugated metal pipe culverts shown in the sketch below (Use the outlet control). The 48-inch diameter culverts have a Manning, n value of 0.024. The culverts are 80 ft long, laid on a slope of 0.04, and have a projecting inlet and outlet. The culvert inlet bottom elevation is 302 ft with a head water elevation of 308.2 ft and a tailwater elevation of 302 ft. Use Ke = 0.8, Ko = 1.0. What is the discharge through the culvert (Use inlet control) with C₁ = 0.62. HW= 308.2 ft H=6.2 ft 302.0 ft BIBIE 3 Parallel CMP D= 48 inch S=0.04 TW 302.0 ft n=0.024 L = 80 ftarrow_forward
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