WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119490579
Author: Mays
Publisher: WILEY
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Chapter 5, Problem 5.3.2P
To determine
The type of water surface profile.
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An unsymmetrical trapezoidal channel with one side inclined from horizontal by 35 degree and the other inclined from vertical by 40degree is to be designed to carry a 2.0 cubic meters per second discharge. Determine the dimensions of the channel for most efficient section if roughness coefficient is 0.030 and average longitudinal slope is 0.05. Draw the cross section of the open channel considering the freeboard height. Use Chezy and Kutter’s C formula.
Determine the hydraulic depth D (average depth) of a triangular channel with right angle corner (900) with a depth of 3 meters.
A trapezoidal channel has a bed width of 5 m, a side slope of 2.5:1 (H:V) and a flow depth of 3 m. The velocity = 1.2 m/s and the velocity head = 0.073 m
i. Determine the flow area (m²) of this channel.
ii. Determine the wetted perimeter (m) of this channel.
iii. Determine the hydraulic radius (m) of this channel.
iv. Determine the width (m) of flow across the surface of this channel.
v. Determine the freeboard (mm) of this channel.
vi. Determine the total channel depth (m).
vii. Determine the discharge (m³/s) of this channel.
viii. Determine the Froude number of the flow.
ix. Comment on the state of flow.…
Chapter 5 Solutions
WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- A trapezoidal channel has a bed width of 5 m, a side slope of 2.5:1 (H:V) and a flow depth of 3 m. The velocity = 1.2 m/s and the velocity head = 0.073 m i. Determine the flow area (m²) of this channel. ii. Determine the wetted perimeter (m) of this channel. iii. Determine the hydraulic radius (m) of this channel. iv. Determine the width (m) of flow across the surface of this channel. v. Determine the freeboard (mm) of this channel. vi. Determine the total channel depth (m). vii. Determine the discharge (m³/s) of this channel. viii. Determine the Froude number of the flow. ix. Comment on the state of flow.…arrow_forward) A) Determine the critical depth in a trapezoidal channel for a discharge of 150 m3/sec. The width of the channel bottom is 6 m, and the side slop upward at angle of 4arrow_forwardDetermine the slope of the channel bed, expressed in the unit of horizontal length to vertical length, given the cross-sectional area of 8 square meters, the wetted perimeter of 8 meters, a volumetric flow rate of 33.33 cubic meters per second, and a Manning's coefficient of 0.012, using the hydraulic principles and the Manning's equation for open channel flow.arrow_forward
- A trapezoidal channel with 3.0 bottom width and 1:1 side slope carries a discharge of 10?3 ? at a slope of 12cm/km. A hydraulic jump is formed in the channel with an initial depth of 0.6 m. Calculate the momentum function, the critical depth, and the conjugate depth.arrow_forwardA trapezoidal channel of bed width 12.0 m, side slopes 2:1, longitudinal bed slope = 10 cm/km, manning n = 0.025 and the critical depth = 0.589 m. If the discharge is doubled, find the corresponding normal water depth and critical deptharrow_forwardIn a rectangular channel, if the water depth just upstream or downstream of a frictionless vertical moving cover is 1.2m and the flow velocity is 2.5m / s , what is the opposite depth?arrow_forward
- An unsymmetrical trapezoidal channel with one side inclined from vertical by 35o and the other inclined from horizontal by 40o is to be designed to carry a 2.5 cubic meters per second discharge. Determine the dimensions of the channel for most efficient section if roughness coefficient is 0.025 and average longitudinal slope is 0.05. Draw the cross section of the open channel considering the freeboard height. Use Chezy and Kutter’s C formula.arrow_forwardA trapezoidal channel with sidewalls of 60 degrees has a bottom width of 4 m at total depth of 5 m and has a constant bedslope of 0.005. A flow of 40 m3/s fills the channel to a depth of 3.5 m, the maximum for normal operation. Downstream a topographic constriction requires that the channel be rectangular with a maximum width of 4 m. Assuming no changes in materials and no energy losses, estimate the depth in the downstream rectangular section and recommend a total depth for the rectangular channel.arrow_forwardWater flows in a trapezoidal channel at a depth of 40cm and with a velocity of 10m/s. An obstruction causes a hydraulic jump to be formed. What is the depth of flow downstream of the jump? The bottom width of the channel is 5m, and the side slopes are 1 vertical to 1 horizontal.arrow_forward
- A trapezoidal channel with these conditions: Left side slope = 3H:2V Right side slope = vertical ... has a bottom width of 4 meters and depth of 6 meters. Determine the hydraulic radius in metersarrow_forwardA trapezoidal channel has a bottom width of ?=6??and sideslopes of ?=2(1?:2? a.Determine the critical depth in this channel if thedischarge is ?=290???.b.calculate and plot the specific energy diagramarrow_forwardA smooth transition section connects two open channels of the same width, as shown in Figure P10.15. The water depth decreases so that the ratio of the downstream to upstream depths Y2/Y1 = 0.5. If the upstream Froude number F1 = 0.35, determine the downstream Froude number F2, and the ratio h/Y1.arrow_forward
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