WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119490579
Author: Mays
Publisher: WILEY
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Chapter 5, Problem 5.4.1P
To determine
The water surface at river mile 1.5.
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Given the drainage area in above Figure calculate the discharge at the outfall using the rational method. Use the5-year rainfall intensity-duration curve Other data are: •for Area 1, C=0.50, Area = 1.3 acres, and inlet time = 7 mins; •for Area 2, C= 0.40 , area = 2.5 acres , and inlet time 5 mins•for Area 3, C=0.70, area 3.9 acres, and andinlet time = 5 mins.The sewer lines in Areas 2 and 3 are each 500 ft in length; and the average velocity of flow in the sewers may be assumed to be 3.0 ft/sec.
Problem 7 - 64
Determine the flow in each pipe in the figure shown and the elevation of
reservoir C if the inflow to reservoir A is 515 Lit/sec.
Problem 7-64 with the following conditions:
- inflow at reservoir A = 600 Ips
- roughness coefficient for all pipes = 0.05
- elevation B = 92m
Use TR-55 graphical method to compute the peak discharge for a 250-ac watershed, with 25-y 24-h rainfall P = 6 in., time of comecntration tc = 1.53 h, runoff curve number CN = 75, and type II rainfall
Chapter 5 Solutions
WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- The flow rates measured during a precipitation at the outlet of a basin with an area of 32400 hectares are given below. It is assumed that the precipitation intensity is constant 60 mm/hr and the infiltration index of the basin is 10 mm/hr. Determine the duration of the unit hydrograph and obtain the 60-minute unit hydrograph of the basin. You can take the base flow as 100 m³/s.arrow_forwardCompute the location of the first gutter inlet from the crest, considering the following information: Maximum allowable flow = 0.35 m3/s Composite runoff coefficient = 0.40 Intensity of rainfall = 125 mm/h Width of drainage area = 75 marrow_forwardThe average flowrate at a small municipal wastewater treatment plant is 20,000 m'/d. The highest observed peak daily flowrate is 50,000 m'id. Design rectangular primary clarifiers with a channel width of 6 m. Use a minimum of two clarifiers, Use an overflow rate of 40 m/m d at average flow and a side water depth of 4 m.arrow_forward
- A trapezoidal channel of 2.0m bed width and 3:2 side slope carries a discharge of 10m3/sec with a depth of flow of 0.5m. Determine whether the flow is supercritical or subcritical. If hydraulic jump where to form. what would be its height and efficiency. Assume mannings coefficient n = 0.025arrow_forwardA rectangular channel of width 550 mm has a discharge of 0.1 m3/s and a uniform flow depth of 250 mm. The channel has an adjustable bottom slope with the value of C equal to 55. Calculate the slope of the channel and the convenience of fume.arrow_forwardPlease answer all. I will rate. A discharge of 1.90 m3/s flows on an open channel with a slope of 0.0062 if the coefficient of roughness is 0.0012, compute the depth (in m) of the channel for optimum discharge using Semi-circular section Choices: 0.36, 1.36, 1.63, 0.63 Rectangular section Choices: 0.58, 1.85, 0.85, 1.58 Triangular section Choices: 1.28, 0.82, 1.82, 0.28arrow_forward
- Find the discharge through a 6” round orifice discharging freely. The water surface elevation in the impoundment is 568’. The elevation at the center of the orifice is 500’. Use a discharge coefficient of 0.62.arrow_forwardWater Resources Engineering: Open Channel Flow A 3.7 meter wide rectangular channel with with a bed slope of 0.00019 and a depth of flow of 2.2 meters. Manning's roughness coefficient is 0.019. Find: a) Can Manning's equation be applied to this system (i.e. Is the flow fully turbulent)? b) Regardless to the answer to part a, determine the steady uniform discharge in the channel (i.e. the "normal depth")arrow_forwardA pipe having a diameter of 3 m with roughness coefficient of 0.013 flows 30% of full depth. If the slope of the energy grade line is 0.0025, determine the discharge.arrow_forward
- A rectangular channel of width 500 mm and a uniform flow depth of 250 mm has a discharge of 0.1 m3/s. The value of C equal of adjustable bottom slope to 55. Calculate the slope of the channel and the convenience of fume.arrow_forwardCompute the specific energy (E) for a channel with a flow depth of 1.3 m, anaverage velocity of 0.8 m/s, and a bed slope of 0.014 m/m. The velocity is non uniformlydistributed across the cross section and the average velocity is taken from a 1/N powerlaw distribution where N = 6.arrow_forwardA pump discharge is 10l / s The NPSHR is 6 m, assun combined K_{L} of 10. The suction pipe diameter is 75 mm. In order to cavitation: a. should the pump be placed below or above the reservoir and b. what is the elevation difference.arrow_forward
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