Concept explainers
(a)
Interpretation: The density of gas at STP should be calculated. If it is greater than the density of air or not should be determined.
Concept Introduction: The density of a substance is its mass per unit volume. It is mathematically represented as follows:
Here, m is mass and V is volume.
At STP, the value of temperature is
Here, P is pressure, V is volume, n is the number of moles, R is Universal gas constant and T is temperature.
Also, the number of moles is related to mass and molar mass as follows:
Here, m is mass and M is molar mass.
Putting the value of the number of moles from equation (3) to (2) thus,
Or,
Putting the value of volume in equation (1) thus,
Or,
(a)
Answer to Problem 5.49P
The density of
Explanation of Solution
The given gas is
The molar mass of the gas is 64.066 g/mol. The pressure and temperature at STP will be 1 atm and 298.15 K thus, density can be calculated using the following relation:
Putting the values,
The density of air at STP is 1.29 g/L. The value of density of
(b)
Interpretation: The density of gas at STP should be calculated. If it is greater than the density of air or not should be determined.
Concept Introduction: The density of a substance is its mass per unit volume. It is mathematically represented as follows:
Here, m is mass and V is volume.
At STP, the value of temperature is
Here, P is pressure, V is volume, n is the number of moles, R is Universal gas constant and T is temperature.
Also, the number of moles is related to mass and molar mass as follows:
Here, m is mass and M is molar mass.
Putting the value of number of moles from equation (3) to (2) thus,
Or,
Putting the value of volume in equation (1) thus,
Or,
(b)
Answer to Problem 5.49P
The density of
Explanation of Solution
The given gas is
The molar mass of the gas is 16.04 g/mol. The pressure and temperature at STP will be 1 atm and 273.15 K thus, density can be calculated using the following relation:
Putting the values,
The density of air at STP is 1.29 g/L. The value of density of
(c)
Interpretation: The density of gas at STP should be calculated. If it is greater than the density of air or not should be determined.
Concept Introduction: The density of a substance is its mass per unit volume. It is mathematically represented as follows:
Here, m is mass and V is volume.
At STP, the value of temperature is
Here, P is pressure, V is volume, n is the number of moles, R is Universal gas constant and T is temperature.
Also, the number of moles is related to mass and molar mass as follows:
Here, m is mass and M is molar mass.
Putting the value of the number of moles from equation (3) to (2) thus,
Or,
Putting the value of volume in equation (1) thus,
Or,
(c)
Answer to Problem 5.49P
The density of
Explanation of Solution
The given gas is
The molar mass of the gas is 1.008 g/mol. The pressure and temperature at STP will be 1 atm and 273.15 K thus, density can be calculated using the following relation:
Putting the values,
The density of air at STP is 1.29 g/L. The value of density of
(d)
Interpretation: The density of gas at STP should be calculated. If it is greater than the density of air or not should be determined.
Concept Introduction: The density of a substance is its mass per unit volume. It is mathematically represented as follows:
Here, m is mass and V is volume.
At STP, the value of temperature is
Here, P is pressure, V is volume, n is the number of moles, R is Universal gas constant and T is temperature.
Also, the number of moles is related to mass and molar mass as follows:
Here, m is mass and M is molar mass.
Putting the value of the number of moles from equation (3) to (2) thus,
Or,
Putting the value of volume in equation (1) thus,
Or,
(d)
Answer to Problem 5.49P
The density of
Explanation of Solution
The given gas is
The molar mass of the gas is 4.002 g/mol. The pressure and temperature at STP will be 1 atm and 273.15 K thus, density can be calculated using the following relation:
Putting the values,
The density of air at STP is 1.29 g/L. The value of density of
(e)
Interpretation: The density of gas at STP should be calculated. If it is greater than the density of air or not should be determined.
Concept Introduction: The density of a substance is its mass per unit volume. It is mathematically represented as follows:
Here, m is mass and V is volume.
At STP, the value of temperature is
Here, P is pressure, V is volume, n is the number of moles, R is Universal gas constant and T is temperature.
Also, the number of moles is related to mass and molar mass as follows:
Here, m is mass and M is molar mass.
Putting the value of the number of moles from equation (3) to (2) thus,
Or,
Putting the value of volume in equation (1) thus,
Or,
(e)
Answer to Problem 5.49P
The density of
Explanation of Solution
The given gas is
The molar mass of the gas is 44.01 g/mol. The pressure and temperature at STP will be 1 atm and 273.15 K thus, density can be calculated using the following relation:
Putting the values,
The density of air at STP is 1.29 g/L. The value of density of
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Chapter 5 Solutions
INTRO.TO GEN.,ORG.,+BIO.-HYBRID ED PKG.
- 5-34 A sample of 30.0 mL of krypton gas, Kr, is at 756 mm Hg and 25.0°C. What is the new volume if the pressure is decreased to 325 mm Hg and the temperature is decreased to-12.5°C?arrow_forward5-41 Does the density of a gas increase, decrease, or stay the same as the pressure increases at constant temperature? As the temperature increases at constant pressure?arrow_forward5-114 Carbon dioxide gas, saturated with water vapor, can be produced by the addition of aqueous acid to calcium carbonate based on the following balanced net ionic equation: (a) How many moles of wet CO (g), collected at 60.°C and 774 torr total pressure, are produced by the complete reaction of 10.0 g of CaCO3 with excess acid? (b) What volume does this wet CO2 occupy? (c) What volume would the CO2 occupy at 774 torr if a desiccant (a chemical drying agent) were added to remove the water? The vapor pressure of water at 60.°C is 149.4 mm Hg.arrow_forward
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- 5-25 A gas in a bulb as in Figure 5-3 registers a pressure of 833 mm Hg in the manometer in which the reference arm of the U-shaped tube (A) is sealed and evacuated. What will the difference in the mercury levels be if the reference arm of the U-shaped tube is open to atmospheric pressure (760 mm Hg)?arrow_forward5-107 If 60.0 g of NH3 occupies 35.1 L under a pressure of 77.2 in. Hg, what is the temperature of the gas, in °C?arrow_forward5-37 A sample of a gas at 77°C and 1.33 atm occupies a volume of 50.3 L. (a) How many moles of the gas are present? (b) Does your answer depend on knowing what gas it is?arrow_forward
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