Explanation The required reaction is given below. 2 N H 3 ( g ) ⇌ N 2 ( g ) + 3 H 2 ( g ) , K c = 0.395 The expression for equilibrium constant for the above reaction can be written as shown below, K c = [ N 2 ] [ H 2 ] 3 [ N H 3 ] 2 Given that, 25.6 g o f N H 3 is placed in a reaction vessel of volume 5.0 L . The concentration of N H 3 can be calculated as given below. [ N H 3 ] = m o l e s v o l u m e = 25.6 g 17.031 g . m o l − 1 5.00 L = 0 . 3 M An equilibrium table can be set up as given below. C o m p o s i t i o n ( M ) N H 3 N 2 H 2 I n i t i a l c o n c e n t r a t i o n 0.3 0 0 C h a n g e i n c o n c e n t r a t i o n − 2 x + x + 3 x E q u i l i b r i u m c o n c e n t r a t i o n 0.3 − 2 x x 3 x Now, these values in the fourth row can be inserted in the equilibrium constant expression as shown below. K c = ( x ) ( 3 x ) 3 ( 0

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ISBN: 9781319420994

Author: ATKINS

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Chapter 5, Problem 5I.32E

Interpretation Introduction

Interpretation:

The equilibrium concentrations of NH3, N2, and H2 has to be calculated. The reaction is given below.

2NH3(g)⇌N2(g)+3H2(g), Kc=0.395

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Chapter 5, Problem 5I.30E

Chapter 5, Problem 5I.33E

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Chapter 5 Solutions

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The equilibrium concentrations of N H 3 , N 2 , a n d H 2 has to be calculated. The reaction is given below. 2 N H 3 ( g ) ⇌ N 2 ( g ) + 3 H 2 ( g ) , K c = 0.395

Solution Summary: The author explains how the equilibrium concentrations of NH_3, N2 and TextText

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Interpretation:

The equilibrium concentrations of NH3, N2, and H2 has to be calculated. The reaction is given below.

2NH3(g)⇌N2(g)+3H2(g), Kc=0.395

Want to see the full answer?

Chapter 5 Solutions

The equilibrium concentrations of N H 3 , N 2 , a n d H 2 has to be calculated. The reaction is given below. 2 N H 3 ( g ) ⇌ N 2 ( g ) + 3 H 2 ( g ) , K c = 0.395

Solution Summary: The author explains how the equilibrium concentrations of NH_3, N­2 and TextText

Videos

Interpretation: The equilibrium concentrations of NH3, N2, and H2 has to be calculated. The reaction is given below. 2NH3(g)⇌N2(g)+3H2(g), Kc=0.395

Want to see the full answer?

Chapter 5 Solutions

Solution Summary: The author explains how the equilibrium concentrations of NH_3, N2 and TextText

Interpretation:

The equilibrium concentrations of NH3, N2, and H2 has to be calculated. The reaction is given below.

2NH3(g)⇌N2(g)+3H2(g), Kc=0.395