Chapter 5, Problem 5E.11E

(a)

Interpretation Introduction

Interpretation:

For the preparation of $0.125mCaC{l}_2\left(aq\right)$ using $500.g$ of water, the mass of ${\text{CaCl}}_{\text{2}}\cdot {\text{6H}}_{\text{2}}\text{O}$ has to be calculated.

Concept introduction:

Number of moles can be calculated by using following formula,

  $No.ofmoles=\frac{Mass\times 1mol}{Molarmass}$

The Molality of the solution can be calculated by using following formula

  $\text{Molality of the solution}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Kg}\text{of}\text{solvent}}$

(b)

Interpretation Introduction

Interpretation:

For the preparation of $0.22m{\text{ NiSO}}_4\left(aq\right)$ using $500.g$ of water, the mass of ${\text{NiSO}}_4\cdot {\text{6H}}_{\text{2}}\text{O}$ has to be calculated.

Concept introduction:

Refer to part (a)