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Chapter 5 Solutions
PHYSICS:F/SCI.+ENGRS.(LL)-W/WEBASSIGN
- A particle moving in the xy plane follows a path described as a function of time by i(t) = (3.4 m/s)tî - (2.8 m/s?)tj. A constant force given by F = (5.0î - 2.0j) N acts on the particle (note that other forces must act on the particle as well if it follows the path given above). (a) Determine the displacement of the particle during the interval t = 1.0 s to t = 4.0 s. AT = îm - m (b) Calculate the work done by F during this interval. W =arrow_forwardA particle of mass 5.70 kg moves in the horizontal xy plane. The only force acting on the particle with component in the xy plane has expression (in newtons) F =4.70x2ı^, where x is in meters. Assume that the particle's trajectory is a straight line from the position (in meters) r0=2.10ı^ +2.10ȷ^ to the position (in meters) rf=6.50ı^ +2.10ȷ^. Also consider that its speed at position r0 has a magnitude of 3.80 m/s. Calculate the magnitude (in m/s) of the particle's velocity at position rf. Give your answer to three significant figures. (only numbers)arrow_forwardThe block of mass m = 2 kg is released from the rest on the incline. If 0 = 15°, what is the velocity of the block 2 seconds after release? Ms = 0.3, k = 0.20 1.288 m/s 3.084 m/s 2.511 m/s m 0 Өarrow_forward
- A 3.5 kg particle moves along an x axis according to x(t) = −12 + 5t2 − 4t3, with xin meters and t in seconds. In unit-vector notation, what is the net force acting on theparticle at t = 6 s?arrow_forwardTwo constant forces act on an object of mass m = 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.50î + 2.15j) m/s. 150° 35.0° (a) Express the two forces in unit-vector notation. F, - N (b) Find the total force exerted on the object. N (c) Find the object's acceleration. m/s2 Now, consider the instant t = 3.00 s. (d) Find the object's velocity. m/s (e) Find its position. (f) Find its kinetic energy from V½mv2. kJ (g) Find its kinetic energy from 2mv,2 + EF · AF. kJarrow_forwardA mass m₁ = 4.0 kg is suspended over a massless frictionless pulley and is attached with a. massless rope to a mass on a frictionless horizontal table, mt = 2.0 kg. This mass is itself attached to another suspended mass m2 = 6.0 kg again with a massless rope over a massless and frictionless pulley. (a) Find the velocity of each mass when m2 falls a distance 20. cm (the masses start atarrow_forward
- Chapter 05, Problem 010 GO A 0.180 kg particle moves along an x axis according to x(t) = - 14.0 + 2.00 t + 4.00 2- 5.00 t, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.30 s ? Give an expression for the (a) x, (b) y and (c) z components. (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER powered by MapleNet ere to search 1:51 PM ENG 4/4/2021 ASUS 19home prt sc pause break delete f10 end f1Pgup f12Pgdn insert & 21 4. 8 backspo-arrow_forwardA drone is being directed across a frictionless ice covered lake. The mass of the drone is 1.50 kg, and its velocity is 3.00i ^ m/s . After 10.0 s, the velocity is 9.00i ^ + 4.00j ^ m/s . If a constant force in the horizontal direction is causing this change in motion, find (a) the components of the force and (b) the magnitude of the force.arrow_forwardAt a particular instant, a 1.0-kg particle’s position is r → = (2.0i ^ − 4.0j ^ + 6.0k ^ )m , its velocity is v → = (−1.0i ^ + 4.0j ^ + 1.0k ^ )m/s , and the force on it is F → = (10.0i ^ + 15.0j ^ )N . (a) What is the angular momentum of the particle about the origin? (b) What is the torque on the particle about the origin? (c) What is the time rate of change of the particle’s angular momentum at this instant?arrow_forward
- A particle of mass 1.05 kg is subject to a force that is always pointed towards the East but whose magnitude changes linearly with time t. The magnitude of the force is given as F = 4t, and has units of newtons. Let the x-axis point towards the East. Determine the change in x-coordinate in meters of the particle Δx between t = 0 and t = 2.4 if the initial velocity is 17.5 m/s, and pointed in the same direction as the force.arrow_forwardTwo forces, 1 = (−6.55î + 4.75ĵ) N and 2 = (−4.05î + 6.40ĵ) N, act on a particle of mass 2.20 kg that is initially at rest at coordinates (+2.30 m, +4.10 m). In what direction is the particle moving at t = 10.1 s? What displacement does the particle undergo during the first 10.1 s? What are the coordinates of the particle at t = 10.1 s?arrow_forwardFor t < 0, an object of mass m experiences no force and moves in the positive x direction with a constant speed vi. Beginning at t = 0, when the object passes position x = 0, it experiences a net resistive force proportional to the square of its speed: net = −mkv2î, where k is a constant. The speed of the object after t = 0 is given by v = vi/(1 + kvit). (a) Find the position x of the object as a function of time. (Use the following as necessary: k, m, t, and vi.)x(t) = (b) Find the object's velocity as a function of position. (Use the following as necessary: k, m, t, vi, and x.) v(t)=arrow_forward
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