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Review. Three forces acting on an object are given by
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Chapter 5 Solutions
PHYSICS:F/SCI.+ENGRS.(LL)-W/WEBASSIGN
- A fish swimming in a horizontal place has velocity v, = (4.0î + 1.0j)m/s at a point in the ocean where the position relative to a rock is ř, = (10.01 – 4.05)m. After the fish swims with constant acceleration for 20 sec its velocity is v = (20.0î – 5.05)m/s. A) What are the components of the acceleration? B) What is the direction of the acceleration with respect to unit vector f? C) If the fish maintains constant acceleration, where is it at t=2.5 s, and in what direction is it moving?arrow_forwardOnly two forces act on an object (mass=3.61 kg), as in the drawing. Find (a) the magnitude and (b) the direction (relative to the x axis) of the acceleration of the object. (a) Number (b) Number i 145.0° 1 40.0 N 60.0 N +X Units Unitsarrow_forwardThe velocity of a particle moving in the x-y plane is given by (6.07i+ 4.97j) m/s at time t = 3.87 s. Its average acceleration during the next 0.014 s is (7.5i + 5.0j) m/s². Determine the velocity v of the particle at t = 3.884 s and the angle between the average- acceleration vector and the velocity vector at t = 3.884 s. Answers: v=i 0= i i+ i j) m/sarrow_forward
- A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15º d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38 EERINarrow_forwardA cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N Find the angle at which the total force is applied. Ans. 62.15° NEERINarrow_forwardA cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i+ 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15°arrow_forward
- You place a crate of mass 39.4 kg on a frictionless 3.67- meter-long incline. You release the crate from rest, and it begins to slide down, eventually reaching the bottom 1.27 s after you released it. What is the angle of the incline? 1 27.6 degrees 2 38.6 degrees 3 57.9 degrees 4 33.1 degreesarrow_forwardThe velocity of a particle moving in the x-y plane is given by (6.98i + 6.68j) m/s at time t = 7.60 s. Its average acceleration during the next 0.014 s is (4.1i + 5.4j) m/s2. Determine the velocity v of the particle at t = 7.614 s and the angle θ between the average-acceleration vector and the velocity vector at t = 7.614 s.Answers:v = ( _____ i + _____ j) m/sθ = _____ °arrow_forwardExpress the force as a Cartesian vector. 180i - 270j -540k180i + 270j - 540k270i - 540j + 180k270i + 540j + 180karrow_forward
- The position vector of a particle of mass 0.05 kg is r (t) = 3 cos (4. t)i + 3 sin (4.t)j +10 t k What is the vector expression for the velocity of the particle at time t in m/s? v (t) = ? What is the vector expression for the acceleration of the particle at time t in m/s^2? a(t) = ? Deduce the magnitude of the force acting on the particle |F| = What is the direction of the acceleration compared with the velocity of the particle?arrow_forwardA skier traveling travelling with a magnitude of velocity v approaches a ramp that has an angle of 0. The approach to the ramp is frictionless, but there is friction on the ramp, and the coefficient of kinetic friction between the skis and the ramp is uk. If the skier travels a distance d up the ramp before coming to a stop, what was their initial velocity v? Your answer for v should be in terms of d, g, uk, and 0. นarrow_forwardThe velocity of a particle moving in the x-y plane is given by (7.15i +4.12j) m/s at time t = 5.37 s. Its average acceleration during the next 0.022 s is (3.9i+ 6.9j) m/s2. Determine the velocity v of the particle at t = 5.392 s and the angle between the average- acceleration vector and the velocity vector at t = 5.392 s. Answers: v = ( i 0= i it i j) m/sarrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning