Chapter 5.1, Problem 65E

(a)

To determine

To write: The latitude and longitude of the Hancock County-Bar Harbour airport in Bar Harbour. Marine, as degrees, minutes and seconds.

Answer to Problem 65E

  $\text{North latitude }{44}^{\circ }26\text{'}59.6\text{'}\text{'}{\text{ West longitude 68}}^{\circ }41\text{'}45.6\text{'}\text{'}$

Explanation of Solution

Given information: Aviation: The locations of two airports are indicated on the map.

Calculation:

  $\text{North latitude = 44}{\text{.4499}}^{\circ }\text{ West longitude = 68}{\text{.2616}}^{\circ }$

To change the decimal parts to minutes, multiply by 60. The whole number will be minutes. Multiply decimal that still exists by 60 again to get the seconds.

Latitude first

  $0.4499\times 60=26.994$

So you get 26’ out of that.

Now multiply the decimal by 60

  $0.994\times 60=59.64\text{'}\text{'}$

So the ${}^{\circ },\text{'},\text{'}\text{'}\text{ is }{44}^{\circ }26\text{'}59.6\text{'}\text{'}$

Now longitude

  $0.2616\times 60=41.76$

So you get 41’ out of that.

Now multiply the decimal by 60

  $0.76\times 60=45.6$

So the ${}^{\circ },\text{'},\text{'}\text{'}\text{ is }{68}^{\circ }41\text{'}45.6\text{'}\text{'}$

  $\text{North latitude }{44}^{\circ }26\text{'}59.6\text{'}\text{'}{\text{ West longitude 68}}^{\circ }41\text{'}45.6\text{'}\text{'}$

(b)

To determine

To write: The latitude and longitude of the Key West International Airport in Key West, Florida, as a decimal to the nearest thousandth.

Answer to Problem 65E

  $\text{North latitude 24}{\text{.5589}}^{\circ }\text{ West longitude 81}{\text{.7596}}^{\circ }$

Explanation of Solution

Given information: Aviation: The locations of two airports are indicated on the map.

Calculation:

  ${\text{North latitude = 24}}^{\circ }{\text{33'32'' West longitude = 81}}^{\circ }45\text{'}34.4\text{'}\text{'}$

To change from minutes to decimal divide by 60

To change from seconds to decimal divide by 3600

Latitude first

  $\begin{array}{l}{24}^{\circ }+\frac{{33}^{\circ }}{60}+\frac{{32}^{\circ }}{3600}={24}^{\circ }+{0.55}^{\circ }+{\mathrm{0.00888...}}^{\circ }\\ ={24.5589}^{\circ }\end{array}$

Now longitude

  $\begin{array}{l}{81}^{\circ }+\frac{{45}^{\circ }}{60}+\frac{34.4}{3600}={81}^{\circ }+{0.75}^{\circ }+{\mathrm{0.009555....}}^{\circ }\\ ={81.7596}^{\circ }\end{array}$

  $\text{North latitude 24}{\text{.5589}}^{\circ }\text{ West longitude 81}{\text{.7596}}^{\circ }$