Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

1st Edition

ISBN: 9780078682278

Author: McGraw-Hill, Berchie Holliday

Publisher: Glencoe/McGraw-Hill

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Question

Chapter 5.8, Problem 32E

(a)

To determine

To find:The distance between the 757 and the tower, if 757 is 20,000 feet from the ground and the angle of depression to the tower is 6∘ .

(a)

Expert Solution

Answer to Problem 32E

191,335.44 feet

Explanation of Solution

Given information: Air Traffic Control: A 757 passenger jet and a 737 passenger jet are on their final approaches to San Diego International Airport.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.8, Problem 32E , additional homework tip 1

Calculation:

Use law of sines to find the distance between the 757 and the tower

20000sin(6∘)=csin(90∘)

Simplify and solve for the distance.

c=191,335.44

Thus,

191,335.44 feet between 757 and the tower

(b)

To determine

To find:The distance between the 737 and the tower, if 737 is 15,000 feet from the ground and the angle of depression to the tower is 3∘ .

(b)

Expert Solution

Answer to Problem 32E

286,609.84 feet

Explanation of Solution

Given information: Air Traffic Control: A 757 passenger jet and a 737 passenger jet are on their final approaches to San Diego International Airport.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.8, Problem 32E , additional homework tip 2

Calculation:

Use law of sines to find the distance between the 737 and the tower

15000sin(3∘)=bsin(90∘)

Simplify and solve for the distance.

b=286,609.84

Thus,

286,609.84 feet between 737 and the tower

(c)

To determine

How far apart are the jets?

(c)

Expert Solution

Answer to Problem 32E

96,059.98 feet apart

Explanation of Solution

Given information: Air Traffic Control: A 757 passenger jet and a 737 passenger jet are on their final approaches to San Diego International Airport.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.8, Problem 32E , additional homework tip 3

Calculation:

Use law of cosines to find the distance between the two planes.

Use 3∘ because 6∘−3∘=3∘

a=286609.842+191335.442−2(286609.84)(191335.44)cos(3∘)

Simplify and solve for the distance between the two planes.

a=96,059.98

Thus,

96,059.98 feet apart

Chapter 5.8, Problem 31E

Chapter 5.8, Problem 33E

Chapter 5 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 5.1 - Prob. 1CFU Ch. 5.1 - Prob. 2CFU Ch. 5.1 - Prob. 3CFU Ch. 5.1 - Prob. 4CFU Ch. 5.1 - Prob. 5CFU Ch. 5.1 - Prob. 6CFU Ch. 5.1 - Prob. 7CFU Ch. 5.1 - Prob. 8CFU Ch. 5.1 - Prob. 9CFU Ch. 5.1 - Prob. 10CFU

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