Concept explainers
Relative to the center of gravity, the torque acting on the seesaw by the mass pk is proportional to the product of that mass with the signed distance of the point xk from c, that is, to (xk – c) · pk. Show that the center of gravity equals the mean of the random variable X. (Hint: To balance, the total torque acting on the seesaw must be 0.)
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- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage