ORGANIC CHEMISTRY MASTERINGCHEM ACCESS
ORGANIC CHEMISTRY MASTERINGCHEM ACCESS
9th Edition
ISBN: 9780137249442
Author: Wade
Publisher: INTER PEAR
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Chapter 5.7, Problem 5.13P
Interpretation Introduction

Interpretation: The percentage of (+)-butan-2-ol and ()-butan-2-ol is to be calculated on the basis of the given information.

Concept introduction: The concentration of the compound affects the rotation of polarized light in Polarimeter. The rotation is also dependent upon the length of the cell and optical activity of the compound. Optical purity of a compound is measured by the enantiomeric excess.

To determine: The percentage of (+)-butan-2-ol and ()-butan-2-ol formed in this reaction on the basis of the given information.

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Explain how the reaction of (CH3)2CHCH(Cl)CH3 with H2O yields two substitutionproducts, (CH3)2CHCH(OH)CH3 and (CH3)2C(OH)CH2CH3
A chemist synthesized compound X as a racemic mixture. When the ketone group in X was enzymatically reduced to the corresponding alcohol, a 100% yield was obtained of the product shown below. Choose the statement that best describes this result. ОН enzyme C;H1 `OCH,CH; pH 4.0 C3H1 `OCH,CH3 ОН ÕH X (racemic) (100% yield) One enantiomer of compound X reacts quickly with the enzyme. The other enantiomer of compound X is unreactive, but rapidly equilibrates with the reactive enantiomer under the reaction conditions. Since compound X was racemic, it makes sense that only a single product was obtained. O The product is a meso compound, so either enantiomer of compound X gives the same product. One enantiomer of compound X reacts quickly with the enzyme, while the other enantiomer of compound X remains unchanged.
for question 25, Why is the answer B vs other options? Thank you
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