Chapter 6, Problem 11RQ

A series circuit contains the following values of resistors:

${\text{R}}_{\text{1}}=510\Omega {\text{ R}}_{\text{2}}=680\Omega {\text{ R}}_{\text{3}}=390\Omega {\text{ R}}_{\text{4}}=750\Omega$

Assume a source voltage of 48 V. Use the general voltage divider formula to calculate the voltage drop across each of the resistors.

${\text{E}}_{\text{1}}=\_\_\_\_\_\_\_\text{V}{\text{ E}}_{\text{2}}=\_\_\_\_\_\_\_\text{V}{\text{ E}}_{\text{3}}=\_\_\_\_\_\_\_\text{V}{\text{ E}}_{\text{4}}=\_\_\_\_\_\_\_\text{V}$