Chapter 6, Problem 15RE

Explanation of Solution

Consider the given information:

Consider the linear search loop given in the textbook Section 6.3.5 using that trace the flow of the below values:

Tracing the flow of linear search loop:

When tracing the flow of linear search loop with the given elements, the values of “pos” and “found” are shown below:

pos	found
0	false
1	false
2	true

Explanation:

In the given loop,

• At first iteration, as the value of “pos” is less than “values.length” and the “!found” is true, the loop condition will be satisfied.
  • The “if” condition checks whether the 0^th position value (that is, “80”) is equal to “100” or not.
    • Here, the condition is “false”, so the else part will increment the “pos” value from “0” to “1”.
• In the second iteration, as the value of “pos” is less than “values.length” and the “!found” is true, the loop condition will be satisfied.
  • The “if” condition checks whether the 1^st position value (that is, “90”) is equal to “100” or not.
    • Here, the condition is “false”, so the else part will increment the “pos” value from “1” to “2”.
• At the third iteration, as the value of “pos” is less than “values.length” and the “!found” is true, the loop condition will be satisfied.
  • The “if” condition checks whether the 2^nd position value (that is, “100”) is equal to “100” or not.
    • Here, the condition is “true”, so the variable “found” will be assigned with the value “true”.
• At the fourth iteration, as the value of “pos” is less than “values.length” and the “!found” is false, the loop will be terminated.

Consider the given information:

Consider the linear search loop given in the textbook Section 6...