A student is given a sample of a pink manganese
a. What was the mass of the hydrate sample?
b. What is the mass of the anhydrous
c. How much water was driven off?
d. What is the percent by mass of water in the hydrate?
e. How many grams of water would there be in
f. How many grams of
g. How many moles of water are present per mole
h. What is the formula of the hydrate?
(a)
Interpretation:
The mass of the hydrated sample of pink manganese
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The mass of the hydrated sample of pink manganese
Explanation of Solution
The sum of the masses of crucible, cover, and sample of a pink manganese
The sum of the masses of crucible and cover
The mass of hydrate can be calculated by the difference between these two mass.
The mass of hydrate is given by the formula as shown below.
Substitute the value of
Therefore, the mass of the hydrate is
The mass of the hydrated sample of pink manganese
(b)
Interpretation:
The mass of the anhydrous
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The mass of the anhydrous
Explanation of Solution
The sum of the masses of crucible, cover, and sample of an anhydrous manganese
The sum of the masses of crucible and cover
The anhydrous
The mass of the anhydrous
Substitute the value of
Therefore, the mass of the anhydrous
The mass of the anhydrous
(c)
Interpretation:
The mass of water released from the hydrated sample of
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The mass of water released from the hydrated sample of
Explanation of Solution
The mass of the anhydrous
The mass of the hydrated sample of pink manganese
The mass of water released on heating can be given by the formula as shown below.
Substitute the mass of hydrate and mass of anhydrate in the above equation.
Therefore, the mass of water released from the hydrated sample is
The mass of water released from the hydrated sample is calculated as
(d)
Interpretation:
The percent by mass of water in the hydrate of
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The percent by mass of water in the hydrate of
Explanation of Solution
The mass of water released from the hydrated sample is
The mass of the hydrated sample of pink manganese
The percent by mass of water in the hydrate is given by the expression as shown below.
Substitute the values of the mass of water and mass of hydrate in the sample in the above equation.
Therefore, the percent by mass of water in the hydrate is
The percent by mass of water in the hydrate is calculated as
(e)
Interpretation:
The mass of water and the number of moles of water in
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The mass of water and the number of moles of water in
Explanation of Solution
The percent by mass of water in the hydrate is
The molar mass of
The number of moles of a substance is given by the expression as shown below.
Where,
•
•
Substitute the values of mass and molar mass of water in the above equation.
Therefore, the number of moles of water in
The mass of water and the number of moles of water in
(f)
Interpretation:
The mass of water and the number of moles of
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The percent by mass of water in the
Explanation of Solution
The mass of the anhydrous
The mass of the hydrated sample of pink manganese
The percent by mass of
Substitute the values of the mass of
The percent by mass of water in the
The molar mass of
The number of moles of a substance is given by the expression as shown below.
Where,
•
•
Substitute the values of the mass and molar mass of
Therefore, the number of moles of
The percent by mass of water in the
(g)
Interpretation:
The number of moles of water present per mole
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The number of moles of water present per mole
Explanation of Solution
The number of moles of
The number of moles of water in
The number of moles of water present per mole
Substitute the value of the number of moles of water and the number of moles of
Therefore, the number of moles of water present per mole
The number of moles of water present per mole
(h)
Interpretation:
The formula of hydrate of
Concept introduction:
The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.
Answer to Problem 1ASA
The formula of hydrate is
Explanation of Solution
The given sample is a pink manganese
The number of moles of water present per mole
Therefore, the formula of hydrate is
The formula of hydrate is
Want to see more full solutions like this?
Chapter 6 Solutions
Chemical Principles in the Laboratory
- is kalburo (calcium carbide) can be mix in fermented cow dung to generate fire?arrow_forwardWhat is the safety precaution associated with handling the crucible, clay triangle, and tripod.? At the beginning of the procedure, why must the crucible be cleaned before weighing? Why must the crucible be heated and allowed to cool before weighing?arrow_forwardDuring smelting, an additional substance is added which combines with impurities to form a fusible product. It is known as:(a) Slag(b) Mud(c) Gangue(d) Fluxarrow_forward
- In order to plate a steel part having a surface area of 0.13 m2 with a 0.05 mm thick layer of nickel: (a) How many atoms of nickel are required? (b) How many moles of nickel are required?arrow_forwardA type of cast iron containing 3-4 wt% C and 1-3 wt% Si. a. Compact graphite b. Malleable cast iron c. Grey Cast iron d. White cast ironarrow_forwardFe2O3 is produced from a pyrite concentrate containing 65% by weight of pyrite (FeS2) by total oxidizing roasting according to the following reaction. 5 tons of pyrite concentrate is roasted daily (MA, g / mol; Fe: 56; S: 32; 0: 16; H: 1). 2FeS2 + 11 / 2O2 → Fe2O3 + 4SO2 How much Fe2O3 is produced in 1 day?arrow_forward
- Hydrofluoric acid etches glass by reacting with the silica in it according to the following equation.ΔH° = 54.5 kJ and ΔS° = 436.5 J mol-1K-1Calculate ΔG° at 25°C for this reaction.arrow_forwardwhich metal Mg or Fe burned at the highest temperature? State the evidence that led to your decision?arrow_forwardWhy does a gold-plated steel post might not offer the same protection as a 14K gold post?arrow_forward
- Explain if coarse grain steel can be carburized?arrow_forward1. a. How many grams of Mn3O4 can be obtained from 1.00 g MnO2? b. how many ounces of Mn3O4 can be obtained from 1.00 lb MnO2? c. What wt of Mn ore should be taken so that the percentage of MnO2 in the ore can be found by multiplyingy 5 to the number of centigrams og Mn3O4arrow_forwardA prospector wants to know how much gold is in the ore that he has been mining. A sample weighing 11.2456 grams is dissolved in Aqua Regia (a mixture of HCl and HNO3). That sample is then transferred to a 200.00 mL volumetric flask and diluted to the mark with water. This is called solution 1. A volumetric pipet is used to transfer 10.00 mL of solution 1 to a second 500.00 mL volumetric flask. The second flask is filled to the mark resulting in solution 2. 5.00 mL of solution 2 is analyzed and found to contain 13.45 ppm Au. Answer each of the questions below. 1. What is the concentration of Au in solution 1. The units should be ppm 2. How many micrograms of Au are in the 5.00 mL sample that was measured? 3. How many micrograms of gold were in the 500.00 mL flask containing solution 2. 4. How many grams Au were in the flask containing solution 1 5. What is the %Au in the original sample?arrow_forward
- Chemical Principles in the LaboratoryChemistryISBN:9781305264434Author:Emil Slowinski, Wayne C. Wolsey, Robert RossiPublisher:Brooks ColeChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
- Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,