One Semester Webassign Access Code for Tipler Physics for Scientists and Engineers
9th Edition
ISBN: 9780716778486
Author: Tipler
Publisher: Macmillan Higher Education
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Chapter 6, Problem 30P
(a)
To determine
The SI units of
(b)
To determine
Work done by force when particle moves from
(c)
To determine
The final velocity of particle.
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Suppose that 23 of work is needed to stretch a spring from its natural length of 36 cm to a length of 47 cm.
(a) How much work (in J) is needed to stretch the spring from 38 cm to 42 cm? (Round your answer to two decimal places.)
0.26
(b) How far beyond its natural length (in cm) will a force of 20 N keep the spring stretched? (Round your answer one decimal place.)
x cm
1
A spring needs a force of 2 N to compress it 18 cm. How much work is required to stretch the spring 54 cm?
ROUND OFF ANSWER UP TO 2 DECIMAL PLACES. INPUT BOTH THE NUMBER AND THE UNIT (ABBREVIATION OF UNIT ONLY).
A spring needs a force of 7 N to compress it 38 cm. How much work is required to stretch the spring 35 cm? (Work is also equal to elastic potential energy.)
ROUND OFF ANSWER UP TO 2 DECIMAL PLACES. INPUT BOTH THE NUMBER AND THE UNIT (ABBREVIATION OF UNIT ONLY).
Chapter 6 Solutions
One Semester Webassign Access Code for Tipler Physics for Scientists and Engineers
Ch. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10P
Ch. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - Prob. 24PCh. 6 - Prob. 25PCh. 6 - Prob. 26PCh. 6 - Prob. 27PCh. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - Prob. 35PCh. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - Prob. 51PCh. 6 - Prob. 52PCh. 6 - Prob. 53PCh. 6 - Prob. 54PCh. 6 - Prob. 55PCh. 6 - Prob. 56PCh. 6 - Prob. 57PCh. 6 - Prob. 58PCh. 6 - Prob. 59PCh. 6 - Prob. 60PCh. 6 - Prob. 61PCh. 6 - Prob. 62PCh. 6 - Prob. 63PCh. 6 - Prob. 64PCh. 6 - Prob. 65PCh. 6 - Prob. 66PCh. 6 - Prob. 67PCh. 6 - Prob. 68PCh. 6 - Prob. 69PCh. 6 - Prob. 70PCh. 6 - Prob. 71PCh. 6 - Prob. 72PCh. 6 - Prob. 73PCh. 6 - Prob. 74P
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- =V.V.) A stone with a mass of 4.00 kg is moving with velocity (6.20î - 1.40ĵ) m/s. (HINT: v² = v (a) What is the stone's kinetic energy (in J) at this velocity? J (b) Find the net work (in J) on the stone if its velocity changes to (8.001 + 4.00ĵ) m/s. Jarrow_forwardA spring whose natural length is 10cm exerts a force of 27N when stretched to a length of 16cm. (a) Find the spring constant (in newtons/meter). k = i N/m (b) Find the work that is done in stretching the spring 2 cm beyond its natural length. Round your answers to four decimals, if necessary. Work = i J (c) Find the work done in stretching the spring from a length of 15cm to a length of 20cm. Round your answers to four decimals, if necessary. Work = i Jarrow_forwardI've already had a wrong Bartleby Expert answer of "1.17" on this question. I am looking for a correct answer please. Do not answer if you are unsure of the answer. Thank you. Suppose that 4 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 41 cm. (a) How much work (in J) is needed to stretch the spring from 28 cm to 36 cm? (Round your answer to two decimal places.)arrow_forward
- If 6 J of work are needed to stretch a spring from 6 cm to 8 cm and 10 J are needed to stretch it from 8 cm to 10 cm, what is the natural length of the spring? cmarrow_forwardIf the work required to stretch a spring 3 ft beyond its natural length is 15 ft-lb, how much work (in ft-lb) is needed to stretch it 18 in. beyond its natural length? Give your answer in decimal form.arrow_forwardA weight lifter raises a 963 N weight a vertical distance of 1.87 m. Compute the work done by the force exerted on the weight by the weight lifter.arrow_forward
- If a particle is moving, it has kinetic energy. Kinetic energy is the energy of motion, and it depends on the speed and mass of the particle. It is given by the formula Ek = 1/2*mv2, where Ek is the kinetic energy, m is the mass, and v is the speed of the particle. The formula for kinetic energy has some important features to keep in mind. Kinetic energy, and every other type of energy as well, is a scalar quantity, given by only a single number. Energy does not have a "direction", unlike a vector quantity. (This is in contrast to the vector quantity momentum, which you might have already studied.) Kinetic energy, in particular, is always a positive number. (Note the speed v is the magnitude of the vector velocity, and therefore is positive. But even if it were a negative number, squaring it would always lead to a positive result.) Kinetic energy depends on the square of the speed. (This is in contrast to the magnitude of momentum, mv, a quantity you may have already studied, which…arrow_forwardPlease answer the following question(s): 1. (a) What is the average useful power output of a person who does 7.0000 x10 J of useful work in 7.0000 hr? P= (b) Working at this rate, how long will it take this person to lift 2100.0000 kg of bricks up a 1.5000-m platform? Hint: Work done to lift his body can be omitted because it is not considered useful output here. t= Search Submit Answer see other options - If you don't want to answer the question right now View Forum Activities (0 new of 0) Powered by CogBooks f6 1- W f7 ♫+ fg Answering the question(s) helps us recommend your next activity. 99+ O fg বিব f10 f11 DDI f12 {9} harrow_forwardSuppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 46 cm. (a) How much work (in J) is needed to stretch the spring from 36 cm to 44 cm? (Round your answer to two decimal places.) J (b) How far beyond its natural length (in cm) will a force of 35 N keep the spring stretched? (Round your answer one decimal place.) cm Need Help? Read It Watch Itarrow_forward
- The work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=∫(F.ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=∫(Fdx). If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.arrow_forwardPower and energy Energy is the capacity to do work, and power isthe rate at which energy is used or consumed. Therefore, if E(t) is theenergy function for a system, then P(t) = E′(t) is the power function. A unit of energy is the kilowatt-hour (1 kWh is the amount ofenergy needed to light ten 100-W light bulbs for an hour); the corresponding units for power are kilowatts. The following figure shows theenergy demand function for a small community over a 25-hour period.a. Estimate the power at t = 10 and t = 20 hr. Be sure to includeunits in your calculation.b. At what times on the interval [0, 25] is the power zero?c. At what times on the interval [0, 25] is the power a maximum?arrow_forwardIf 3 J of work is needed to stretch a spring from 13 cm to 15 cm and another 5 J is needed to stretch it from 15 cm to 17 cm, what is the natural length (in cm) of the spring?arrow_forward
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