Contemporary Engineering Economics (6th Edition)
Contemporary Engineering Economics (6th Edition)
6th Edition
ISBN: 9780134105598
Author: Chan S. Park
Publisher: PEARSON
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Chapter 6, Problem 52P
To determine

Calculate the annual cost.

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Advanced Electrical Insulator Company is considering replacing a brokeninspection machine, which has been used to test the mechanical strength of electrical insulators with a newer and more efficient one. If repaired, the old machine can be used for another five years although the firm does not expect to realize any salvage value from scrapping it in five years. Alternatively, the firm can sell the machine to another firm in the industry now for $5,000. If the machine is kept, it will require an immediate $1,200 overhaul to restore it to operable condition. The overhaul will neither extend the service life originally estimated nor increase the value of the inspection machine. The operating costs are estimated at $2,000 during the first year and are expected to increase by $1,500 per year thereafter. Future market values are expected to decline by $1,000 per year. The new machine costs $10,000 and will have operating costs of $2,000 in the first year, increasing by $800 per year…
You are evaluating two different silicon wafer milling machines. The Techron I costs $228,000, has a three-year life, and has pretax operating costs of $59,000 per year. The Techron II costs $400,000, has a five-year life, and has pretax operating costs of $32,000 per year. For both milling machines, use straight-line depreciation to zero over the project’s life and assume a salvage value of $36,000. If your tax rate is 24 percent and your discount rate is 8 percent, compute the EAC for both machines. Note: Your answer should be a negative value and indicated by a minus sign. Do not round intermediate calculations and round your answers to 2 decimal places, e.g., 32.16.
Two 150-horsepower (HP) motors are being considered for installation at amunicipal sewage treatment plant. The first costs $4,500 and has an operating efficiency of 83%. The second costs $3,600 and has an operating efficiency of 80%. Both motors are projected to have zero salvage value after a life of 10 years. All the annual charges, such as insurance and maintenance, amount to a total of 15% of the original cost of each motor. If power cost is a flat 5 cents per kilowatt-hour, which alternative should be chosen at 5,000 operating hours per year? Assume an interest rate of 6%. (A conversion factor you might find useful is IHP = 746watts = .746kilowatts.)
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