The ionization energy of an atom can be measured by photo electron spectroscopy, in which light of wavelength λ is directed at an atom, causing an electron to be ejected. The kinetic energy of the ejected electron ( E K ) is measured by determining its velocity, v since E K = 1 / 2 m v 2 . The E i is then calculated using the relationship that the energy of the incident light equals the sum of E i plus E K . (a) What is the ionization energy of rubidium atoms in kilojoules per mole if light with λ = 58.4 nm produces electrons with a velocity of 2.450 × 10 6 m/s ? (The mass ofan electron is 9.109 × 10 − 31 kg .) (b) What is the ionization energy of potassium in kilojoulesper mole if light with λ = 142 nm produces electrons witha velocity of 1 .240×10 6 m/s ?
The ionization energy of an atom can be measured by photo electron spectroscopy, in which light of wavelength λ is directed at an atom, causing an electron to be ejected. The kinetic energy of the ejected electron ( E K ) is measured by determining its velocity, v since E K = 1 / 2 m v 2 . The E i is then calculated using the relationship that the energy of the incident light equals the sum of E i plus E K . (a) What is the ionization energy of rubidium atoms in kilojoules per mole if light with λ = 58.4 nm produces electrons with a velocity of 2.450 × 10 6 m/s ? (The mass ofan electron is 9.109 × 10 − 31 kg .) (b) What is the ionization energy of potassium in kilojoulesper mole if light with λ = 142 nm produces electrons witha velocity of 1 .240×10 6 m/s ?
Solution Summary: The author explains that energy is directly related to frequency and is expressed by Planck-Einstein equation.
The ionization energy of an atom can be measured by photo electron spectroscopy, in which light of wavelength
λ
is directed at an atom, causing an electron to be ejected. The kinetic energy of the ejected electron
(
E
K
)
is measured by determining its velocity, v since
E
K
=
1
/
2
m
v
2
. The
E
i
is then calculated using the relationship that the energy of the incident light equals the sum of
E
i
plus
E
K
. (a) What is the ionization energy of rubidium atoms in kilojoules per mole if light with
λ
=
58.4
nm
produces electrons with a velocity of
2.450
×
10
6
m/s
? (The mass ofan electron is
9.109
×
10
−
31
kg
.) (b) What is the ionization energy of potassium in kilojoulesper mole if light with
λ
=
142
nm
produces electrons witha velocity of
1
.240×10
6
m/s
?
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
The Bohr Model of the atom and Atomic Emission Spectra: Atomic Structure tutorial | Crash Chemistry; Author: Crash Chemistry Academy;https://www.youtube.com/watch?v=apuWi_Fbtys;License: Standard YouTube License, CC-BY