Concept explainers
(a)
The flow rate in each pipe.
Answer to Problem 6.113P
Explanation of Solution
Given information:
The total flow rate is equal to
The loss of co-efficient is equal to
The volumetric flow rate Q can be defined as below,
In the above equation,
The energy equation is defined as,
Where the head loss
The friction factor can be determined by,
The Reynolds’s number is defined as,
For parallel pipe flow,
Assume, the water at
Calculation:
For parallel pipe flow, we can say
Substitute for known values,
For pipe 1, the energy equation can be defined as,
Head loss can be written as,
Guess
Substitute for known values,
Similarly for pipe 2,
Energy equation can be written as,
Therefore, the head loss is equal to,
Guess
Substitute for known values,
But we know that,
Therefore,
Solve equation 1 & 2 to find relevant velocities,
According to equation 2,
Substitute in equation 1,
Therefore we get,
Calculate the relevant Reynolds’s numbers,
Calculate the roughness ratio,
For pipe 1,
For pipe 2,
Calculate the relevant friction factors,
For pipe 1,
By solving,
For pipe 2,
By solving,
Calculate the relevant velocities for the above found friction factors,
Substitute in equation 2,
Solve further,
Substitute in equation 1,
Therefore we get,
Now, find the relevant flow rates,
Conclusion:
The flow rate in pipe 1 is equal to
The flow rate in pipe 2 is equal to
(b)
The overall pressure drop.
Answer to Problem 6.113P
Explanation of Solution
Given information:
The total flow rate is equal to
The loss of co-efficient is equal to
The pressure drop is defined as,
Assume, the water at
Calculation:
The pressure drop is same in both pipes, therefore,
For pipe 1,
Substitute for known values,
Conclusion:
The pressure drop is equal to
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Chapter 6 Solutions
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