   Chapter 6, Problem 6.12P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

The maximum and minimum dry unit weights of a sand were determined in the laboratory to be 16.9 kN/m3 and 14.2 kN/m3, respectively. What is the relative compaction in the field if the relative density is 82%?

To determine

Find the relative compaction in the field for 82 % relative density.

Explanation

Given information:

The maximum dry unit weight of the sand γdmax is 16.9kN/m3.

The minimum dry unit weight of the sand γdmin is 14.2kN/m3.

The relative density (Dr) is 82 %.

Calculation:

Determine the field dry unit weight using the relation.

Dr=[γd(field)γd(min)γd(max)γd(min)][γd(max)γd(field)]

Substitute 82 % for Dr, 14.2kN/m3 for γd(min), and 16.9kN/m3 for γd(max).

82100=[γd(field)14.216.914.2][16.9γd(field)]0

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