(a)
Interpretation:
The given reaction proceeds to right or left to attain equilibrium has to be predicted.
Concept introduction:
Equilibrium constant (K):
In the equilibrium reaction, the ratio of concentration of the reactant and concentration of the product.
Reaction quotient (Q): It is defined as the ratio between concentration of the product and concentration of the reactant.
This value used to know about the direction of the reaction is going to proceed.
If
If
If
(a)
Answer to Problem 6.12P
The reaction should be go to the right.
Explanation of Solution
Given
Given reaction is,
Amount of
Amount of
Amount of
Temperature =
To calculate: Q value
Where,
(b)
Interpretation:
The pressure (Pa) of each species at equilibrium has to be calculated.
(b)
Answer to Problem 6.12P
Explanation of Solution
Given
Given reaction is,
Amount of
Amount of
Amount of
Temperature =
To calculate: pressure (Pa) of each species at equilibrium
So, the value of x has to be subtracted from the final pressure to get pressure.
(c)
Interpretation:
The reaction proceed to left or the right to regenerate the equilibrium when the mixture is compressed to half of its original volume has to be explained.
Concept introduction:
Equilibrium constant (K):
In the equilibrium reaction, the ratio of concentration of the reactant and concentration of the product.
Reaction quotient (Q): It is defined as the ratio between concentration of the product and concentration of the reactant.
This value used to know about the direction of the reaction is going to proceed.
If
If
If
(c)
Explanation of Solution
Given
Given reaction is,
Amount of
Amount of
Amount of
Temperature =
To explain: reaction proceed to left or the right to regenerate the equilibrium when the mixture is compressed to half of its original volume
The reaction proceeds neither to left nor to right to regenerate the equilibrium when the mixture is compressed to half of its original volume. Since Q is remains the same.
(d)
Interpretation:
Concept introduction:
(d)
Explanation of Solution
Given
Given reaction is,
Amount of
Amount of
Amount of
Temperature =
To explain:
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Chapter 6 Solutions
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