Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 6, Problem 6.16P
To determine
Find the significant depth of densification.
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For a dynamic compaction test, weight of hammer = 15 metric tons; height of drop = 12 m. Determine the significant depth of influence for compaction D in meters.
The maximum density of the sample by the standard compaction test is 1.76 g/cm3 at an optimum moisture content of 14.5% Find the degree of saturation (G=2.68).
The maximum density of the sample by the standard compaction test is 1.76 g/cm3 at an optimum moisture content of 14.5% Find the air voids (G=2.68).
a.8.8%
b.7.7%
c.10.10%
d.9.9%
Chapter 6 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- Note: Add 0.16 to the results on table before solving.a. Determine the maximum dry unit weight and OMC.b. What is the dry unit weight and moisture range at 95 % relative compaction?c. Determine the degree of saturation at the maximum dry density if Gs = 2.70.arrow_forwardThe relative compaction of a sand in the field is 90%. The maximum and minimum dry unit weights of the sand are 17 kN/m3 and 14.5 kN/m3, respectively. For the field condition determine the dry unit weightarrow_forwardFor a normally consolidated laboratory clay specimen drained on both sides, the following are given: σ0’ = 4000 ib/ft² e=1.2 σ0’ + Δσ’= 5000 lb/ft² e=0.9 Thickness of clay specimen= 2in Time for 50% consolidation= 2 min. Determine the hydraulic conductivity (ft/min) of the clay for the loading range. How long (in days) will it take for a 6-ft clay layer in the field(drained on both side) To reach 60% consolidation?arrow_forward
- The nominal compactive effort (NCE) used for standard proctor test is 600 kJ/m3 300 kJ/m3 6000 kJ/m3 1000 kJ/m3arrow_forwardThe relative compaction of a sand in the field is 94%. Given the dry unit weight maximum= 16.2 kN/m3 and the dry unit weight minimum = 14.9 kN/m3.For the field conditions Compute the relative density of compactionarrow_forwardThe results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m3) of compaction and the optimum moisture contentarrow_forward
- Determine the compaction effort of Standard Proctor Test in English unit Method A. (ft − lb/ft^3)arrow_forward3. The following table lists the results of a standard Proctor assay. Determine the maximum dry compaction density and the optimum moisture content. Also obtain the void ratio and degree of saturation for optimum moisture content. Assume Gs = 2.68.arrow_forwardThe maximum density of the sample by the standard compaction test is 1.76 g/cm3 at an optimum moisture content of 14.5% (G=2.68). What would be the corresponding value of the dry density on the zero air voids line at optimum water content.arrow_forward
- The degree of compaction of sand in the field is 93.5%. Considering a dry specific weight maximum “γd max” and minimum “γd min” (see Table 1) of this sand determine the dry specific weight in field and its relative compression compactness.arrow_forwardPlot the moisture density curve and determine the maximum dry unit weight of compaction and the optimum moisture content.arrow_forwardThe relative compaction of sand in the field is 95. The max dry unit weight of the sand is 16 kN/cum. Compute the moist unit weight at a moisture content of 8%arrow_forward
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