Given Information : A 4-way set associative cache is given: Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A 1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02 2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E 3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2 4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA 5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A 6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1 FA 93 EB 48 7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30 The number of physical address bits is represented by “m”. The size of cache represented is by “C”. The block of size in bytes is represented as “B”. Associativity is represented as “E”. The number of cache sets is represented by “S”. The number of tag bits is represented by “t”. The number of block offset bits is represented as “b”.

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Answer 1

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

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If memory read cycle takes 100 ns and a cache read cycle takes 20 ns, then for four continuous references, the first one brings the main memory contents to cache and the next three from cache. Find the time taken for the Read cycle with and without Cache? What is the Percentage speedup obtained?

A cache has been designed such that it has 512 lines, with each line or block containing 8 words. Identify the line number, tag, and word position for the 20- bit address 3A45616 using the direct mapping method.

For the main memory address FEDCBAH, show the following information in hexadecimal format: 1)Tag, Line, and Word values for a direct-mapped cache 2)Tag and Word values for an associative cache 3)Tag, Set, and Word values for a two-way set-associative cache

Answer 2

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Expert Solution & Answer

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Answer 3

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

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Answer 4

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

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Answer 5

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 6

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 7

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

Ch. 6.1 - Prob. 6.1PP Ch. 6.1 - Prob. 6.2PP Ch. 6.1 - Prob. 6.3PP Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Prob. 6.5PP Ch. 6.1 - Prob. 6.6PP Ch. 6.2 - Prob. 6.7PP Ch. 6.2 - Prob. 6.8PP Ch. 6.4 - Prob. 6.9PP Ch. 6.4 - Prob. 6.10PP

Solution Summary: The author explains that a 4-way set associative cache is given. The number of physical address bits is represented by "m".

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Chapter 6 Solutions

Index	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3
0	F0	1	ED 32 0A A2	8A	1	BF 80 1D FC	14	1	EF 09 86 2A	BC	0	25 44 6F 1A
1	BC	0	03 3E CD 38	A0	0	16 7B ED 5A	BC	1	8E 4C DF 18	E4	1	FB B7 12 02
2	BC	1	54 9E 1E FA	B6	1	DC 81 B2 14	00	0	B6 1F 7B 44	74	0	10 F5 B8 2E
3	BE	0	2F 7E 3D A8	C0	1	27 95 A4 74	C4	0	07 11 6B D8	BC	0	C7 B7 AF C2
4	7E	1	32 21 1C 2C	8A	1	22 C2 DC 34	BC	1	BA DD 37 D8	DC	0	E7 A2 39 BA
5	98	0	A9 76 2B EE	54	0	BC 91 D5 92	98	1	80 BA 9B F6	BC	1	48 16 81 0A
6	38	0	5D 4D F7 DA	BC	1	69 C2 8C 74	8A	1	A8 CE 7F DA	38	1	FA 93 EB 48
7	8A	1	04 2A 32 6A	9E	0	B1 86 56 0E	CC	1	96 30 47 F2	BC	1	F8 1D 42 30