Engineering Electromagnetics
Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Chapter 6, Problem 6.5P
To determine

The factor by which capacitance is increased.

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A parallel-plate capacitor consists of square plates of edge length ℓ that are separated by a distance d, where d << ℓ. A potential difference ΔV is maintained between the plates. A material of dielectric constant k fills half the space between the plates. The dielectric slab is withdrawn from the capacitor as shown. (a) Find the capacitance when the left edge of the dielectric is at a distance x from the center of the capacitor. (b) If the dielectric is removed at a constant speed υ, what is the current in the circuit as the dielectric is being withdrawn?
A parallel plate capacitor contains two dielectrics A and B (interfaces parallel to E and D) with relative permittivity of 1.5 and 3.5 respectively. Dielectric B comprises one third of the capacitor's volume and the remaining volume is occupied by dielectric A. If the area of each conducting plate is 3 square meters and the separation between them is 2 mm, find the capacitance
Two coaxial conducting cylinders are located at ρ = 2 cm and ρ = 4 cm in free space and have a length of 100 m. The region between the cylinders contains a layer of dielectric from ρ = 2 cm to ρ = 3.69 cm with εr = 2. The capacitance in nF is?

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Engineering Electromagnetics

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