Concept explainers
a)
Interpretation: The ionization energy of molecular hydrogen is greater than atomic hydrogen should be explained. Also, the ionization energy of molecular oxygen is lower than atomic oxygen should be explained.
Concept introduction: Two or more than two atomic orbitals overlap to form bond, these orbitals are called molecular orbitals. Count of molecular orbital obtained is same as count of atomic orbitals mixed.
Two forms of molecular orbital are obtained. These are bonding and antibonding orbital.
Bonding orbitals are those in that electrons are in between nucleus of two atom. Antibonding orbitals are those in which electrons are away from nucleus of two-atom. Also, electrons in antibonding orbital have energy high as compared to bonding orbital.
In sigma
In pi
In pi
b)
Interpretation: The relative ionization energies of atomic and molecular fluorine should be determined.
Concept introduction: Two or more than two atomic orbitals overlap to form bond, these orbitals are called molecular orbitals. Count of molecular orbital obtained is same as count of atomic orbitals mixed.
Two forms of molecular orbital are obtained. These are bonding and antibonding orbital.
Bonding orbitals are those in that electrons are in between nucleus of two atom. Antibonding orbitals are those in which electrons are away from nucleus of two-atom. Also, electrons in antibonding orbital have energy high as compared to bonding orbital.
In sigma
In pi
In pi
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OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI
- Three biologically Important diatomic species,either because they promote or inhibit life, are (a) CO, (b) NO, and (c) CN−. The first binds to hemoglobin, the second is a chemical messenger, and the third interrupts the respiratory electron transfer chain. Their biochemical action is a reflection of their orbital structure. Deduce their ground-state electron configurations using sigma and pi. (Draw MO)arrow_forwardQUESTION 5 (31 MARKS) (a) (i) Draw a pz orbital and a d?-y² orbital. (4) (ii) What are the differences between a 5pz orbital and a 4d,- orbital in the H atom? (6) (b) (i) Draw the Lewis structure of methanol, CH3OH(8). (3) (ii) Show with a simple diagram how methanol dissolves in water. Explain. (2) (c) How does the energy and length of the carbon-oxygen bond in CH3OH(e) compare with the carbon-oxygen distance in carbon monoxide? Explain. (5) (d) Chemical bonds can be classified as polar covalent, according to and (3) (e) Chemical bonds can also be classified as single or number of according to the (2) (f) Draw the Lewis structure(s) for SO3F. Explain the structure which you have drawn. (6)arrow_forwardChemical species are said to be isoelectronic if they have the same Lewis structure (regardless of charge). Consider these ions and write a Lewis structure for a neutral molecule that is isoelectronic with them. (a) CN–, (b) NH4+ (c) CO3 2–arrow_forward
- Some chemical reactions proceed by the in it ial loss or transfer of an electron to a diatomic species. Which of the molecules N2, NO. O2, C2, F2, and CN would you expect to be stabil ized by (a) the addit ion of an electron to form AB-. (b) the removal of an electron to form AB+?arrow_forwardIn addition to ammonia, nitrogen forms three other hydrides: hydrazine (N2H4), diazene (N2H2), and tetrazene (N4H4).(a) Use Lewis structures to compare the strength, length, and order of the nitrogen-nitrogen bonds in hydrazine, diazene, and N2.(b) Tetrazene (atom sequence H2NNNNH2) decomposes above 08C to hydrazine and nitrogen gas. Draw a Lewis structure for tetrazene, and calculate ΔH°rxn for this decomposition.arrow_forwardIn addition to ammonia, nitrogen forms three other hy-drides: hydrazine (N₂H₄), diazene (N₂H₂), and tetrazene (N₄H₄).(a) Use Lewis structures to compare the strength, length, and or-der of nitrogen-nitrogen bonds in hydrazine, diazene, and N₂.(b) Tetrazene (atom sequence H₂NNNNH₂) decomposes above 0°C to hydrazine and nitrogen gas. Draw a Lewis structure fortetrazene, and calculate ΔH°ᵣₓₙ for this decomposition.arrow_forward
- (c) Draw the orbital diagrams and Lewis symbols to depict the formation of Na* and CI ions from the atoms. Give the formula of the compound formed. (d) The predicted bond length for HF is 109 pm (the sum of the covalent radii of H, 37 pm and F. 72 pm), however the actual bond length for HF is shorter (92 pm). It was observed that the difference between predicted and actual bond lengths becomes smalleor going down the halogen group from HF to HI Describe these observationsarrow_forwardMixing SbCl3 and GaCl3 in a 1:1 molar ratio using liquid sulfur dioxide as a solvent gives a solidionic compound with the empirical formula GaSbCl6. A controversy arose over whether this compoundis [SbCl2]+[GaCl4]− or [GaCl2]+[SbCl4]−.(a) Predict the molecular structure of the two anions from the two choices using VSEPR theory.(b) It is learned that the cation in the compound has a bent structure. Based on this fact, whichformulation is the correct one?arrow_forward(b) List some properties of Group 1 elements which indicate they are all metals. (c) What valence do all Group 1 elements exhibit in their compounds? (a) Write the names and symbols of the elements of Group 2.arrow_forward
- N2 and CN' are both isoelectronic. (i) Draw the molecular orbital diagram for N2 and CN molecules. (ii) Explain why CN is a toxic substance but N2 isn't. (iii) N2(g) is an inert gas that is suitable for a wide range of application. Would you expect N2" to be a stable diatomic species in the gaseous state? Explain your answer.arrow_forwardWhat energy is possessed by .... A. Water held by a dam B. A book in its edge before falling What is the valency of aHydroxyl ion ? If an element X with atomic number of 11 and nitrogen of 7 what is the most likely formula of nitride of X pH2O2——->qH2O+O2. What are the values of p and qarrow_forwardFor the O2+ ion predict (a) number of unpaired electrons, (b) bond order, (c) bond enthalpy and bond length.arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning