The MO of the ground state of a heteronuclear diatomicmoleculeAB is
If a bonding electron spends 90% of its time in an orbital
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Chapter 6 Solutions
OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI
- The photoelectron spectrum of HBr has two main groups of peaks. The first has ionization energy 11.88 eV. The next peak has ionization energy 15.2 eV, and it is followed by a long progression of peaks with higher ionization energies. Identify the molecular orbitals corresponding to these two groups of peaks.arrow_forwardUse the data in Table 3.1 to plot the logarithm of ionization energy versus the number of electrons removed for Ne. Describe the electronic structure of the Ne atom.arrow_forwardGiven that the following MO-energy-level diagram applies to the the diatomic molecular cation BO+, match the letter label of each energy level with the corresponding orbital descriptor. (See attached image!) O2pσ2pσ2s*π2pσ2p*B+2sπ2p*σ2sO2sB+2p Does this diagram display the effect of s-p orbital mixing? YES or NO? Which kind of magnetism would be observed for this cation? paramagnetism diamagnetism What is the bond order for this cation? 0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 2.0arrow_forward
- Considering a homonuclear diatomic 2 pis molecule, the parity label "gerade" (or "g") indicates that there is a change in sign of the orbitals when passing through the center of the molecule. * O True O Falsearrow_forwardThe MO of the ground state of a heteronuclear diatomic molecule AB is Vmol = CA4A + CB4B If a bonding electron spends 90% of its time in an orbital pA on atom A and 10% of its time in øB on atom B, what are the values of CA and Cg? (Neglect the overlap of the two orbitals.)arrow_forwardDerive the bonding Ψ of mixing atomic orbitals φA +φB + φC.arrow_forward
- why do you not need to specify the molecular shap for an atom with 1 electron grouparrow_forwardWrite the electronic hamiltonian for HeH+.arrow_forwardConsider a N2 molecule in its first excited electronic state. (a) Identify the molecular orbitals involved and sketch a diagram to show the transition (b) Compare the bond order and bond length of N2* with N2, where the asterisk denotes the excited molecule. (c) Is N2* diagmagnetic or paramagnetic? (d) When N2* loses its excess energy and converts to the ground state N2, it emits a photon of wavelength 470 nm. Calculate the energy difference between these levels. thank you so mucharrow_forward
- Write the va lence bond wavefunction of a P2 molecule. Why is P4 a stable form of molecular phosphorus?arrow_forwarda.) Based on their ground state electron configurations alone, rank these molecule in order of bond dissociation energy from smallest to greatest:A = N2B = B2C = O2. b.) Based on their ground state electron configurations alone, rank these molecule in order of bond length from smallest to greatest:A = N2B = O2C = NOarrow_forwardThe electronic structure 1s2s22p63s23p64s23d104p65s24d6 refers to the ground state of Xe Ru. Rh. O Tc. O Fe.arrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning
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