Solid Waste Engineering
3rd Edition
ISBN: 9781305635203
Author: Worrell, William A.
Publisher: Cengage Learning,
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Textbook Question
Chapter 6, Problem 6.9P
Estimate the production of CO2 and CH4 during the anaerobic decomposition of ethanol. C2H6O.
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Determine the theoretical oxygen demands for the following chemicals and show the balanced stoichiometric equations with your work: a) 150 mg/L ethanol, b) 0.5 mg/L pentachlorophenol (chloride will end up being OCl- when oxidized), and c) 100 mg/L isopropanol
Environmental Engineering
When methanol is used to generate hydrogen, it reacts with the following reaction:
CH3OH>>>>CO+2H2
The reaction is second order in methanol, and it is observed that 100g of carbon monoxide can be produced in one day in a batch reactor, if you start with 200g of methanol. What is the rate constant for this reaction?
The Bunsen burner in your labs are fueled by natural gas, which is mostly methane, CH4. The
thermochemical equations for the combustion of methane (burning in oxygen) is:
CH4(g) + 2 O2(g) ➔ CO2(g) + 2 H2O (g) ΔH = – 890.3 kJ/mole
Calculate ΔH in kJ when 5.00 g CH4 react with an excess oxygen.
Chapter 6 Solutions
Solid Waste Engineering
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- Cellulose is to be burned in a waste-to- energy fadlity. The chemical equation for cellulose C6 H10O5is the atomic weights of C, H, and O are 12, 1, and 16. respectively. a. Calculate the stoichiometric oxygen necessary for the combustion of cellulose. b. Calculate stoichiometric air.arrow_forwardThe ideal equation for the combustion of cellulose is C6H10O5 + 6O26O2 + 5H2O. What is a similar idealized equation for pyrolysis? What end products might you expect?arrow_forwardCellulose is to be burned in a waste to energy facility. The chemical equation for cellulose is C6H10O5. The atomic weights of C, H, and O are 12, 1, and 16, respectively. The ideal equation for the combustion of cellulose is C6H10O5 +6O2à6CO2 + 5H2O. Calculate the stoichiometric oxygen necessary for the combustion of cellulose. Calculate the stoichiometric air supply. The air is 23.15% oxygen by weight. If the facility operates at 1.5 tons/hour at 100% excess air. How much air is required?arrow_forward
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- An incinerator burns 180 lb/hr chlorobenzene and has a stack gas containing 7% oxygen by volume on a dry basis. Determine the percent excess air .arrow_forwardYou are treating 10 million gallons per day (MGD) of water with alum at a dosage of 50.0 mg/L. Alum is available as a hydrated salt Al2(SO4)3.16H2O. Determine:(a) The monthly alum dosage required in metric tons/month (1 metric ton = 1000 kg)(b) If you assume that each equivalent of alum added to the water consumes 1 equivalent of alkalinity, determine the alkalinity consumed by alum addition in milliequivalents/L (meq/L)(c) Given that the raw water contained 30 mg/L as CaCO3 of alkalinity, is the alkalinity sufficient? What would happen if the alkalinity is inadequate?arrow_forwardChloroform, CHCl3 a volatile liquid, was once used as an anesthetic but has been replaced by safer compounds. Chloroform boils at 61.7°C and has a heat of vaporization of 31.4 kJ/mol. What is its vapor pressure at 37.2°C?arrow_forward
- Calculate the Theoretical Oxygen demand if 500 mg/L of bepridil, must be oxidized completely in Lair/Lsol ?arrow_forwardDesign a laboratory scale chemostat to aerobically treat a 10 liters per day of a synthetic wastewater containing 500 mg/L of glucose. In order to design and operate such a chemostat you will need to not only need to calculate the volume of the reactor, but you also need to determine the amount of oxygen that must be supplied and at what rate, and the amount of biomass produced and the composition of the effluent (i.e., effluent COD and biomass concentration). Make reasonable assumptions for all necessary parameters you may need for this problem. Make sure to check units of parameters assumed.arrow_forwardPlease solve and show all work with units Determine the total Theoretical oxygen demand for both carbon and nitrogen compound containing a total oxygen required for NO2- of 100 mg/l and the sample Nh4+ originally having 14 mg/l as N. C6H12O6N2 + O2 + H+ ➔ CO2 + H2O + NH4 + NH4 + + O2 ➔ NO2 - + H+ + H2O NO2 - + O2 ➔ NO3 -arrow_forward
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