Chapter 6, Problem 7MC

Which of the following is an inmemory copy of data pulled from one or more database tables? 1. Table adapter 2. Table relation 3. Dataset 4. Data record

You are working with an Access data base that has two tables you joined for a particular query. The tables and contents are: Auto table contains vin (text and primary key), make (text), model (text), color (text), mileage (number) Rental table contains customer# (number and part of primary key), date (date and part of primary key), vin code (text and part of primary key) Assuming you joined the table correctly, which of the following correctly limits the records displayed to those where the mileage is greater than 50000? Select one: a. mileage<50000 b. mileage>50000 c. mileage>#50000# d. mileage>"50000"

134. EMPDET is an external table containing the columns EMPNO and ENAME. Which command would work in relation to the EMPDET table? a. UPDATE empdetSET ename = 'Amit'WHERE empno = 1234; b. DELETE FROM empdetWHERE ename LIKE 'J%'; c. CREATE VIEW empvuASSELECT * FROM empdept; d. CREATE INDEXempdet_idxON empdet(empno);

Which of the following is NOT an issue specific to MariaDB?       Substition variables do not work (& and &&)     Group functions cannot include single row functions in the same statement     || is not CONCATE by default     Column aliases are not case sensitive

Which of the following is true of foreign keys?     A foreign key should always be linked to a primary key of another table. A foreign key could be linked to a candidate key of a table. A foreign key is not needed if the data type is different. A foreign key can be linked to any foreign key.

Which one of the following statements regarding views is true? Creating views can improve query response time due to caching. View could be considered an additional layer of security on the underlying table which enables the DBA to protect intricate or sensitive data but still allow access. Views are virtual tables that are materialized at run time and as needed All of the statement are true

in the question it said that "Assume that the Reward and Department tables have already been created " so i don't need to create the tables + there is a link from rewards and department to the Employee as in the picture for a reference, my answer is : CREATE TABLE Employee ( EMP_ID CHAR(3) NOT NULL,FNAME VARCHAR(15) NOT NULL,LNAME VARCHAR(15) NOT NULL,SALARY DECIMAL(10,2),JOIN_DATE DATEDEP_NO CHAR(2) NOT NULLPRIMARY KEY(EMP_ID),FOREIGN KEY(EMP_ID) REFRENCE Rewrad,FOREIGN KEY(DEP_NO) REFRENCE Department                                                                        );is it wrong ?

CONSIDER THE INVOICE TABLE BELOW: invoice id                       NUMBER (12), invoice date                   DATE,Invoice total                   NUMBER (9, 2), payzent_total                 NUBER (9, 2), credit total                      NUMBER (9, 2),invoice due date            DATE, payrent date                  DATE,CIL REC user                VARCHAR2 (12),CTL SEC level               NUMBER (1)Consider the INVOICE table structure below: A trigger is created on the INVOICE table: CREATE OR REPLACE TRIGGER rg_On_Quiz before insert or update on Invoice FOR EACH ROW DECLARE V_level Number; V_name VARCHAR (20); Begin SELECT USERNAME, SECURITY_LEVEL INTO V_name, V_level FROM AUTHORIZED_USERS WHERE USERNAME = USER; :NEW.CTL_REC_user := V_name; :NEW.CTL_REC_user := V_level; EXCEPTION WHEN NO_DATA_FOUND THEN RAISE_APPLICATION_ERROR (-2003, 'UNAUTHORIZED USER'); END; In Oracle/PLSQL, the USER function returns the user_id from the current Oracle session. a.) Explain what this triger does…

I need the output of the queries      create table Accounts (account_no number primary key, client_name varchar2(200),Gender varchar2(20),address Varchar2(200)); create table loans (branch_id number, bank_name varchar2(200),Loan number, loan_Status varchar2(200),account_no number references Accounts(account_no) ON DELETE CASCADE);   1. delete from accounts where account_no= 101; 2. select * from accounts  a where exists (select 1 from loans l where l.account_no= a.account_no) 3. select * from accounts a  where exists (select 1 from loans l  where l.account_no= a.account_no and status = 'accepted') 4. create or replace view view1 as select client_name , address,l.bank_name,l.loan_Status from accounts a, loans l where a.account_no = l.account_no Step 2 5.create or replace view view2  as  select client_name , address,l.bank_name,l.loan_Status from accounts a, loans l where a.account_no = l.account_no and address = 'Karachi' 6. create or replace view view3 as  select client_name ,…