Optimal solution

Here in this case if the available carpentry hours remain between 60 and 100, then the current basis remains optimal.

But a change in the right hand side of the constraint will not make the basis optimal.

If the right hand side of the constraint is changed, then both the constraints remains feasible...

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Chapter 6.1, Problem 1P

Chapter 6.1, Problem 3P

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Consider that there are four items that can fit inside a 13-pound-capacity backpack. The respective weights of the items are 5.7, 4, and 3 pounds. Their respective utilities are 8, 11, 6, and 4 utils. Determine the optimal solution that maximizes the overall usefulness of the backpack.

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Operations Research : Applications and Algorithms

Ch. 6.1 - Prob. 1P Ch. 6.1 - Prob. 2P Ch. 6.1 - Prob. 3P Ch. 6.1 - Prob. 4P Ch. 6.1 - Prob. 5P Ch. 6.2 - Prob. 1P Ch. 6.2 - Prob. 2P Ch. 6.3 - Prob. 1P Ch. 6.3 - Prob. 2P Ch. 6.3 - Prob. 3P

Ch. 6.3 - Prob. 4P Ch. 6.3 - Prob. 5P Ch. 6.3 - Prob. 6P Ch. 6.3 - Prob. 7P Ch. 6.3 - Prob. 8P Ch. 6.3 - Prob. 9P Ch. 6.4 - Prob. 1P Ch. 6.4 - Prob. 2P Ch. 6.4 - Prob. 3P Ch. 6.4 - Prob. 4P Ch. 6.4 - Prob. 5P Ch. 6.4 - Prob. 6P Ch. 6.4 - Prob. 7P Ch. 6.4 - Prob. 8P Ch. 6.4 - Prob. 9P Ch. 6.4 - Prob. 10P Ch. 6.4 - Prob. 11P Ch. 6.4 - Prob. 12P Ch. 6.4 - Prob. 13P Ch. 6.5 - Prob. 1P Ch. 6.5 - Find the duals of the following LPs: Ch. 6.5 - Prob. 3P Ch. 6.5 - Prob. 4P Ch. 6.5 - Prob. 5P Ch. 6.5 - Prob. 6P Ch. 6.6 - Prob. 1P Ch. 6.6 - Prob. 2P Ch. 6.7 - Prob. 1P Ch. 6.7 - Prob. 2P Ch. 6.7 - Prob. 3P Ch. 6.7 - Prob. 4P Ch. 6.7 - Prob. 5P Ch. 6.7 - Prob. 6P Ch. 6.7 - Prob. 7P Ch. 6.7 - Prob. 8P Ch. 6.7 - Prob. 9P Ch. 6.8 - Prob. 1P Ch. 6.8 - Prob. 2P Ch. 6.8 - Prob. 3P Ch. 6.8 - Prob. 4P Ch. 6.8 - Prob. 5P Ch. 6.8 - Prob. 6P Ch. 6.8 - Prob. 8P Ch. 6.8 - Prob. 9P Ch. 6.8 - Prob. 10P Ch. 6.8 - Prob. 11P Ch. 6.9 - Prob. 1P Ch. 6.9 - Prob. 2P Ch. 6.9 - Prob. 3P Ch. 6.10 - Prob. 1P Ch. 6.10 - Prob. 2P Ch. 6.10 - Prob. 3P Ch. 6.11 - Prob. 1P Ch. 6.11 - Prob. 3P Ch. 6.11 - Prob. 4P Ch. 6.12 - Prob. 5P Ch. 6.12 - Prob. 6P Ch. 6.12 - Prob. 7P Ch. 6 - Prob. 1RP Ch. 6 - Prob. 2RP Ch. 6 - Prob. 3RP Ch. 6 - Prob. 4RP Ch. 6 - Prob. 5RP Ch. 6 - Prob. 6RP Ch. 6 - Prob. 7RP Ch. 6 - Prob. 8RP Ch. 6 - Prob. 9RP Ch. 6 - Prob. 10RP Ch. 6 - Prob. 11RP Ch. 6 - Prob. 13RP Ch. 6 - Prob. 14RP Ch. 6 - Prob. 15RP Ch. 6 - Prob. 17RP Ch. 6 - Prob. 18RP Ch. 6 - Prob. 19RP Ch. 6 - Prob. 20RP Ch. 6 - Prob. 21RP Ch. 6 - Prob. 22RP Ch. 6 - Prob. 25RP Ch. 6 - Prob. 29RP Ch. 6 - Prob. 33RP Ch. 6 - Prob. 34RP Ch. 6 - Prob. 35RP Ch. 6 - Prob. 36RP Ch. 6 - Prob. 37RP

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Solution Summary: The author explains that if the available carpentry hours remain between 60 and 100, then the current basis remains optimal, but a change in the right hand side of the constraint will not make the basis optimal.

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