Chapter 6.2, Problem 10CFU

To determine

To find: the linear velocity (round to the nearest tenth).

Answer to Problem 10CFU

  $432.0\text{ inches per second}$

Explanation of Solution

Given information:

  $\begin{array}{l}\text{Angular velocity }\left(\omega \right)=36\text{ radians per second}\\ \text{Distance from the center of rotating object}\left(r\right)=12\text{ inches}\end{array}$

Calculation:

The linear velocity $\left(\upsilon \right)$ of a point at given angular velocity and distance from centre of rotating object is evaluated as follows:

  $\begin{array}{c}\upsilon =r\omega \\ =\left(36\right)\left(12\right)\left[\text{Put the values of }r\text{ and }\omega \right]\\ =432.0\text{ inches per second}\end{array}$

Thus the linear velocity is 432.0 inches per second.