Chapter 6.5, Problem 54E

To determine

To find: the amount of water (in gallons) that is required to raise the level of water.

Answer to Problem 54E

7854 gallons

Explanation of Solution

Given information:

Length of swimming pool $\left(l\right)$ = 75 feet

Width of swimming pool $\left(w\right)$ = 42 feet

Level to be raise $\left(h\right)$ = 4 inches

  $\text{7}\text{.48 gallons }=1\text{ cubic foot}$

Calculation:

Evaluate the volume of swimming pool as follows:

  $\begin{array}{c}V=l\times w\times h\\ =75\times 42\times \frac{1}{3}\left[\text{4 inches = }\frac{1}{3}\text{ feet}\right]\\ =1050{\text{ ft}}^3\\ =1050{\text{ ft}}^3\left(\frac{\text{7}\text{.48 gallons }}{1{\text{ft}}^3}\right)\\ =7854\text{ gallons}\end{array}$

Thus,the amount of water (in gallons) that is required to raise the level of water is 7854 gallons.