Explanation Given: The height and radius of the right circular cone: h = 4 meter r = 1.2 meter Density of the material is 600 k g / m 3 Calculation: Think the column as a stack of n thin layers of width δ y = 4 n . Now, first compute the gravitational force on a thin layer of width δ y . It is given that that the height and square base of the right circular cone. Then, the volume of the solid box is V = area × width ⇒ V = π 3 1.44 δ y m 3 Now to find the mass of the structure. As density = mass volume ⇒ mass = volume × density ⇒ mass = π 3 × 1.44 δ y × 600 ⇒ mass = 904.32 δ y k g Now, as per newton’s rule, force of the solid box is f = m g f = 904.32 δ y × 9.8 f = 8862.33 δ y N The work performed in lifting in this layer to height y is equal to the force time the distance y , which is ( 8862.33 δ y ) y

ACHIEVE FOR CALCULUS 1 TERM >CSI CUSTOM<

4th Edition

ISBN: 9781319411657

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 6.5, Problem 13E

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the work against gravity required to build the structure out of a lightweight.

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Chapter 6.5, Problem 12E

Chapter 6.5, Problem 14E

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Chapter 6 Solutions

ACHIEVE FOR CALCULUS 1 TERM >CSI CUSTOM<

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the work against gravity required to build the structure out of a lightweight.

Solution Summary: The author calculates the work against gravity required to build the structure out of a lightweight.

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To calculate: the work against gravity required to build the structure out of a lightweight.

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Chapter 6 Solutions

To calculate:

the work against gravity required to build the structure out of a lightweight.