INTRO TO CHEMISTRY EBK ACCESS CARD >I<
5th Edition
ISBN: 9781260916430
Author: BAUER
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 7, Problem 121QP
Interpretation Introduction
Interpretation:
The wavelength, frequency, and the energy of light absorbed and released as indicated by the different colors are to be explained.
Concept Introduction:
The
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
104. Photogray lenses incorporate small amounts of silver chloride in the glass of the lens.
The following reaction occurs in the light, causing the lenses to darken:
AgCl(s) → Ag(s) + Cl
The enthalpy change for this reaction is 3.10 × 102 kJ/mol. Assuming all this energy is
supplied by light, what is the maximum wavelength of light that can cause this reaction?
ANS: 3.86 x 10-7 m
PAGE: 7.1
A ceramic plate has a shiny rim. The ceramic plate is mostly composed of silicon and oxygen atoms. The shiny rim is mostly silver. When the plate is heated in a microwave oven, sparks are observed. Compare the ionization energy values of silver to those of the silicon and oxygen atoms. Explain what is happening in the oven. Why are microwaveable containers usually non-metallic? Why are most pots and pans metallic?
Astronomers observe spectra of planetary nebulae to learn about the stars that created
them, and to understand how planetary nebulae contribute to the chemical enrichment
of the Milky Way Galaxy over time. In order to determine the chemical abundances in
nebulae, astronomers need to know the temperature of the gas and its density. Sulfur
emission lines are useful for determining density in planetary nebulae.
Certain electron transitions involve energy levels that are said to be metastable; the
resulting emission lines are called "forbidden" lines, which really only means that they
are less likely to occur than emission lines from the ordinary kind of transitions.
lons and electrons in a planetary nebula are always moving and bumping into each
other. The energy exchanged in these collisions isn't enough to strip off electrons, but it
is enough to kick an electron to a higher energy level within the ground state. In fact,
the only way that these higher levels can be populated is by…
Chapter 7 Solutions
INTRO TO CHEMISTRY EBK ACCESS CARD >I<
Ch. 7 - Prob. 1QCCh. 7 - Prob. 2QCCh. 7 - Prob. 3QCCh. 7 - Prob. 4QCCh. 7 - Prob. 5QCCh. 7 - Prob. 6QCCh. 7 - Prob. 7QCCh. 7 - Prob. 1PPCh. 7 - Prob. 2PPCh. 7 - Prob. 3PP
Ch. 7 - Prob. 4PPCh. 7 - Prob. 5PPCh. 7 - Prob. 6PPCh. 7 - Prob. 7PPCh. 7 - Prob. 8PPCh. 7 - Prob. 9PPCh. 7 - Prob. 10PPCh. 7 - Prob. 11PPCh. 7 - Prob. 1QPCh. 7 - Match the key terms with the descriptions...Ch. 7 - Prob. 3QPCh. 7 - Prob. 4QPCh. 7 - Prob. 5QPCh. 7 - Prob. 6QPCh. 7 - Prob. 7QPCh. 7 - Prob. 8QPCh. 7 - Prob. 9QPCh. 7 - Prob. 10QPCh. 7 - Prob. 11QPCh. 7 - Prob. 12QPCh. 7 - Prob. 13QPCh. 7 - Prob. 14QPCh. 7 - Prob. 15QPCh. 7 - Prob. 16QPCh. 7 - Prob. 17QPCh. 7 - Prob. 18QPCh. 7 - Prob. 19QPCh. 7 - Prob. 20QPCh. 7 - Prob. 21QPCh. 7 - Prob. 22QPCh. 7 - Bohr proposed that the electron in a hydrogen atom...Ch. 7 - Prob. 24QPCh. 7 - Prob. 25QPCh. 7 - Prob. 26QPCh. 7 - Prob. 27QPCh. 7 - Prob. 28QPCh. 7 - Prob. 29QPCh. 7 - Prob. 30QPCh. 7 - Prob. 31QPCh. 7 - In the Bohr model, which of the following electron...Ch. 7 - Prob. 33QPCh. 7 - Prob. 34QPCh. 7 - Prob. 35QPCh. 7 - Prob. 36QPCh. 7 - Prob. 37QPCh. 7 - Prob. 38QPCh. 7 - Prob. 39QPCh. 7 - Prob. 40QPCh. 7 - Prob. 41QPCh. 7 - Prob. 42QPCh. 7 - Prob. 43QPCh. 7 - Prob. 44QPCh. 7 - Prob. 45QPCh. 7 - Complete the following orbital diagrams for the...Ch. 7 - Prob. 47QPCh. 7 - Prob. 48QPCh. 7 - Prob. 49QPCh. 7 - Prob. 50QPCh. 7 - Prob. 51QPCh. 7 - Prob. 52QPCh. 7 - Prob. 53QPCh. 7 - Prob. 54QPCh. 7 - Prob. 55QPCh. 7 - Prob. 56QPCh. 7 - Prob. 57QPCh. 7 - Prob. 58QPCh. 7 - Prob. 59QPCh. 7 - Prob. 60QPCh. 7 - Prob. 61QPCh. 7 - Prob. 62QPCh. 7 - Prob. 63QPCh. 7 - Prob. 64QPCh. 7 - Prob. 65QPCh. 7 - Prob. 66QPCh. 7 - Prob. 67QPCh. 7 - Prob. 68QPCh. 7 - Prob. 69QPCh. 7 - Prob. 70QPCh. 7 - Prob. 71QPCh. 7 - Prob. 72QPCh. 7 - Prob. 73QPCh. 7 - Prob. 74QPCh. 7 - Prob. 75QPCh. 7 - Prob. 76QPCh. 7 - Prob. 77QPCh. 7 - Prob. 78QPCh. 7 - Prob. 79QPCh. 7 - Prob. 80QPCh. 7 - Prob. 81QPCh. 7 - Write the complete and abbreviated electron...Ch. 7 - Prob. 83QPCh. 7 - Prob. 84QPCh. 7 - Prob. 85QPCh. 7 - Prob. 86QPCh. 7 - Prob. 87QPCh. 7 - Prob. 88QPCh. 7 - Prob. 89QPCh. 7 - Prob. 90QPCh. 7 - Prob. 91QPCh. 7 - Prob. 92QPCh. 7 - Prob. 93QPCh. 7 - Prob. 94QPCh. 7 - Prob. 95QPCh. 7 - Prob. 96QPCh. 7 - Prob. 97QPCh. 7 - Prob. 98QPCh. 7 - Prob. 99QPCh. 7 - Prob. 100QPCh. 7 - Prob. 101QPCh. 7 - Prob. 102QPCh. 7 - Prob. 103QPCh. 7 - Prob. 104QPCh. 7 - Prob. 105QPCh. 7 - Prob. 106QPCh. 7 - Which is the larger ion, K+orCa2+? Explain.Ch. 7 - Prob. 108QPCh. 7 - Prob. 109QPCh. 7 - Prob. 110QPCh. 7 - Prob. 111QPCh. 7 - Prob. 112QPCh. 7 - Prob. 113QPCh. 7 - Prob. 114QPCh. 7 - Prob. 115QPCh. 7 - Prob. 116QPCh. 7 - Prob. 117QPCh. 7 - Prob. 118QPCh. 7 - Prob. 119QPCh. 7 - Prob. 120QPCh. 7 - Prob. 121QPCh. 7 - Prob. 122QPCh. 7 - Prob. 123QPCh. 7 - Prob. 124QPCh. 7 - Prob. 125QPCh. 7 - Prob. 126QPCh. 7 - Prob. 127QPCh. 7 - Prob. 128QPCh. 7 - Prob. 129QPCh. 7 - Prob. 130QPCh. 7 - Prob. 131QPCh. 7 - Prob. 132QPCh. 7 - Prob. 133QPCh. 7 - How many unpaired electrons are in a single atom...Ch. 7 - Prob. 135QPCh. 7 - Which element has a ground-state electron...Ch. 7 - Which of the following is the correct abbreviated...Ch. 7 - Prob. 138QPCh. 7 - Prob. 139QPCh. 7 - Prob. 140QPCh. 7 - Prob. 141QPCh. 7 - Prob. 142QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Sunburn is caused by ultraviolet UV radiation. Why does red light not cause sunburn?arrow_forwardThe following shapes each represent an orbital of an atom in a hypothetical universe. The small circle is the location of the nucleus in each orbital. a If you placed an electron in each orbital, which one would be higher in energy? b When an electron makes a transition from the orbital represented on the right to the orbital on the left, would you expect energy to be absorbed or released? c Draw a sketch of an orbital of the same type that would be higher in energy than either of the two pictured orbitals.arrow_forwardAssign a correct set of four quantum numbers for (a) Each electron in a nitrogen atom. (b) The valence electron in a sodium atom. (c) A 3d electron in a nickel atom.arrow_forward
- Photogray lenses incorporate small amounts of silver chloride in the glass of the lens. When light hits the AgCl particles, me following reaction occurs: AgClhvAg+Cl The silver metal that is formed causes the lenses to darken. The energy change for this reaction is 3.10 102 kJ/mol. Assuming all this energy must be supplied by light, what is the maximum wavelength of light that can cause this reaction?arrow_forwardHow many unpaired electrons are there 111 the following ions? (a) V3+(b) Sn4+(c) I-(d) W4+arrow_forward● What are valence electrons? Noble gases are sometimes called "inert gases." How do their electron configurations explain why noble gases do not participate in many chemical reactions? If fluorine gains 1 electron, which element will it be similar to?_ If sodium loses 1 electron, which element will it be similar to?_ What group of elements are the "other elements" striving to be similar to?arrow_forward
- Co forms two monatomic ions, Co³t and Co²+. From which sublevels do you expect electrons are lost in forming these ions? (Hint: It is possible for electrons other than those in the s and p sublevels to be involved in forming ions.) In forming the Co3+ ion are: electron(s) lost from the 4s orbital? electron(s) lost from the 3d orbital? To support your answer, complete the following. It is OK to use the noble gas core notation. (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s 1 or in condensed form as [He]2s '.) Electron configuration of Co: 3+ Electron configuration of Co*arrow_forwardPhotoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and molecules. High-energy radiation (usually UV or X-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the measured energy of the electron lost. The following energy differences were determined for several electron transitions: ΔE2 →1 = 4.098 ×10−17 J ΔE3 →1 = 4.854 × 10−17 JΔE5 → 1 = 5.242 ×10−17 J ΔE4 → 2 = 1.024 ×10−17 J Calculate the energy change and the wavelength of a photon emitted in the following transitions. Enter your answers in scientific notation. Use 6.626 ×10−34 J·s for Planck's constant. (a) Level 3 to 2: ______J ______m (b) Level 4 to 1: _____J_____ m (c) Level 5 to 4: _____J _____marrow_forwardPhotoelectron spectroscopy removes one electron from an atom or molecule and measures ionization energies. When this process was used with Sc metal, the Sc* ions formed in three different states (see below). Rank these three states according to the ionization energies needed to produce each one (smallest to largest). I. 4s 3d I. 4s 3d II. 4s 3d 十+arrow_forward
- The electron configuration can also be represented by writing the symbol for the occupied subshell and adding a superscript to indicate the number of electrons in that subshell. For example, consider a carbon atom having an atomic number of 6. The total number of electrons in a neutral carbon atom is 6. The electron configuration of the carbon atom represented by the orbital diagram is This electron configuration can be written as C-1111 18 28 2p 1² 28² 2p² where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells Use the rules for determining electron configurations to write the electron configuration for Ca Express your answer in complete form in order of orbital filling. For example, 1s 2s should be entered as 15 225 2. ▸ View Available Hint(s)arrow_forward#5 pleasearrow_forwardOne way to measure ionization energies is photoelectron spectroscopy (PES), a technique based on the photoelectric effect. In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm. (Figure 1) Figure lonization energy (kJ/mol) 2500 2000 1500 1000 500 0 419 Rb 403 496 1A 2A 549 Ha 509 H 1312 $20 M Na 738 Be 899 Ca 990 801 Al 786 Sa 709 558 PD 11 710 Ga 762 Ge 947 941 579 S 1012 1000 BE 703 Sb 834 O 1402 1314 Po 812 Increasing ionization energy s 1251 Te 1008 SAY 1681 Kr Se 1140 Be 1351 Xo 1170 Rn 1037 3A 4A SA 6A 7A SA He Increasing ionization energyarrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Quantum Mechanics - Part 1: Crash Course Physics #43; Author: CrashCourse;https://www.youtube.com/watch?v=7kb1VT0J3DE;License: Standard YouTube License, CC-BY