Discrete Mathematics - Student Solutions Manual - Dossey - Paperback
Discrete Mathematics - Student Solutions Manual - Dossey - Paperback
5th Edition
ISBN: 9780321305176
Author: Dossey, SPENCE, OTTO, Eynden
Publisher: Pearson Education
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Chapter 7, Problem 1SE
To determine

The maximal flow and a minimal cut for given network by starting with the flow that is 0 along every arc by flow augmentation algorithm.

Expert Solution & Answer
Check Mark

Answer to Problem 1SE

The maximal flow and minimal cut for the given network is {A}_ and {B,C,D,E,F}_.

Explanation of Solution

Given:

The network is shown in Figure 1.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  1

Concept used:

Flow Augmentation Algorithm

For a transportation network in which arc (X,Y) has capacity c(X,Y), this algorithm either indicates that the current flow f is a maximal flow or else replaces f with a flow having a larger value.

Step 1 (Label the source)

Label the source with the triple (source,+,).

Step 2 (Scan and label)

Step 2.1 (select a vertex to scan)

Among all the vertices that have been labeled, but not scanned. Let V denote the one that was labeled first, and suppose that the label on V is (U,±,a).

Step 2.2 (scan vertex V)

For each unlabeled vertex W, perform exactly one of the following three actions:

(a) If (V,W) is an arc and f(V,W)<c(V,W), assign to W the label (V,+,b), where b is the smaller of a and c(V,W)f(V,W).

(b) If (W,V) is an arc and f(W,V)>0, assign to W the label (V,,b) where b is the smaller of a and f(W,V).

(c) If neither (a) and (b) holds, do not label W.

Step 2.3 (mark as scanned)

Regard vertex V as having been scanned.

Until either the sink is labeled or every labeled vertex has been scanned.

Step 3 (increase the flow if possible)

If the sink is unlabeled the present flow is a maximal flow.

Otherwise

Step 3.1 (breakthrough)

Let V denote the sink and suppose that the label on V is (U,+,a).

Step 3.2 (adjust the flow)

(a) If the label on V is (U,+,b) then replace f(V,U) with f(V,U)a.

(b) If the label on V is (U,,b) then replace f(V,U) with f(V,U)a.

(c) Let V denote the vertex U.

Until V is the source.

Calculation:

The given network is shown in Figure 1.

Label the given network as shown in Figure 2.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  2

Consider the path A,B,D,F and label it as shown in Figure 3.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  3

Increase the flow by 5 in the path A,B,D,F and label the path A,B,E,F as shown below in Figure 4.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  4

Increase the flow by 2 in the path A,B,E,F and label the path A,C,D,E,F as shown below in Figure 5.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  5

Increase the flow by 4 in the path A,C,D,E,F and label the path A,C,F as shown below in Figure 6.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  6

Increase the flow by 4 in the path A,C,F as shown below in Figure 7.

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback, Chapter 7, Problem 1SE , additional homework tip  7

The labeled vertices are A and unlabeled vertices are B,C,D,E,F.

Label the sets as S={ A } and T={B,C,D,E,F}.

Therefore, the minimal cut for the given network is {A} and {B,C,D,E,F}.

Thus, the above flow shown in Figure 7 has maximal flow and minimal cut for the given network is {A}_ and {B,C,D,E,F}_.

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Chapter 7 Solutions

Discrete Mathematics - Student Solutions Manual - Dossey - Paperback

Ch. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.2 - Prob. 1ECh. 7.2 - Prob. 2ECh. 7.2 - Prob. 3ECh. 7.2 - Prob. 4ECh. 7.2 - Prob. 5ECh. 7.2 - Prob. 6ECh. 7.2 - Prob. 7ECh. 7.2 - Prob. 8ECh. 7.2 - Prob. 9ECh. 7.2 - Prob. 10ECh. 7.2 - Prob. 11ECh. 7.2 - Prob. 12ECh. 7.2 - Prob. 13ECh. 7.2 - Prob. 14ECh. 7.2 - Prob. 15ECh. 7.2 - Prob. 16ECh. 7.2 - Prob. 17ECh. 7.2 - Prob. 18ECh. 7.2 - Prob. 19ECh. 7.2 - Prob. 20ECh. 7.2 - Prob. 21ECh. 7.2 - Prob. 22ECh. 7.2 - Prob. 23ECh. 7.2 - Prob. 24ECh. 7.2 - Prob. 25ECh. 7.2 - Prob. 26ECh. 7.2 - Prob. 27ECh. 7.2 - Prob. 28ECh. 7.2 - Prob. 29ECh. 7.2 - Prob. 30ECh. 7.3 - Prob. 1ECh. 7.3 - Prob. 2ECh. 7.3 - Prob. 3ECh. 7.3 - Prob. 4ECh. 7.3 - Prob. 5ECh. 7.3 - Prob. 6ECh. 7.3 - Prob. 7ECh. 7.3 - Prob. 8ECh. 7.3 - Prob. 9ECh. 7.3 - Prob. 10ECh. 7.3 - Prob. 11ECh. 7.3 - Prob. 12ECh. 7.3 - In Exercises 13–14, a network with rational arc...Ch. 7.3 - Prob. 14ECh. 7.3 - Prob. 15ECh. 7.3 - Prob. 16ECh. 7.3 - Prob. 17ECh. 7.3 - Prob. 18ECh. 7.3 - Prob. 19ECh. 7.3 - Prob. 20ECh. 7.3 - Prob. 22ECh. 7.3 - Prob. 23ECh. 7.3 - Prob. 24ECh. 7.3 - Prob. 25ECh. 7.4 - Prob. 1ECh. 7.4 - Prob. 2ECh. 7.4 - Prob. 3ECh. 7.4 - Prob. 4ECh. 7.4 - Prob. 5ECh. 7.4 - Prob. 6ECh. 7.4 - Prob. 7ECh. 7.4 - Prob. 8ECh. 7.4 - Prob. 9ECh. 7.4 - Prob. 10ECh. 7.4 - Prob. 11ECh. 7.4 - Prob. 12ECh. 7.4 - Prob. 13ECh. 7.4 - Prob. 14ECh. 7.4 - Prob. 15ECh. 7.4 - Prob. 16ECh. 7.4 - Prob. 17ECh. 7.4 - Prob. 18ECh. 7.4 - Prob. 19ECh. 7.4 - Prob. 20ECh. 7.4 - Prob. 21ECh. 7.4 - Prob. 22ECh. 7.4 - Prob. 23ECh. 7 - Prob. 1SECh. 7 - Prob. 2SECh. 7 - Prob. 3SECh. 7 - In Exercises 1–8, find a maximal flow and a...Ch. 7 - Prob. 5SECh. 7 - Prob. 6SECh. 7 - Prob. 7SECh. 7 - Prob. 8SECh. 7 - Prob. 15SECh. 7 - Prob. 16SECh. 7 - Prob. 17SECh. 7 - Prob. 21SECh. 7 - Prob. 22SECh. 7 - Prob. 24SE
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