ESSENTIALS OF GENETICS ALC & MOD MSTG/ET VP
1st Edition
ISBN: 9780134452890
Author: KLUG
Publisher: Pearson Education
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Chapter 7, Problem 21PDQ
In Drosophila, Dichaete (D) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny with a Dichaete
| Phenotype | Number |
| Dichaete | 401 |
| ebony, pink | 389 |
| Dichaete, ebony | 84 |
| pink | 96 |
| Dichaete, pink | 2 |
| ebony | 3 |
| Dichaete, ebony, pink | 12 |
| wild type | 13 |
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In Drosophila, Dichaete (D) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny, with a Dichaete phenotype, were backcrossed to the ebony, pink homozygotes. Using the results of this backcross shown in the table,
(a) Diagram this cross, showing the genotypes of the parents and offspring of both crosses.
(b) What is the sequence and inter locus distance between these three genes?
In Drosophila, vermilion eye color is due to a recessive allele (v) located on the X chromosome. Curved wings are due to a recessive allele (cu) located on one autosome, and ebony body is due to a recessive allele (e) located on another autosome. A vermilion male is mated to a curved, ebony female, and the F1 males are phenotypically wild-type. If these males were backcrossed to curved, ebony females, what proportion of the F2 offspring will be wild-type males?
One of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y+, v+, and f+ (but not B+) was inverted with respect to the normal order of genes. This female was crossed to a wild- type male in the cross diagrammed her.
The cross produced the following male offspring:* table in figure
a. Why are there no male offspring with the allele combinations y v f+, v+ v+ f, y v+ f+, or y+ v f (regardless of the allele of the Bar eye gene)?b. What kinds of crossovers produced the y v f b+ and v+ y+ f+ B offspring? Can you determine any genetic distances from these classed of progeny?c. What kinds of crossovers produced the y+ v f+ B+ and y v+ f B offspring?
Chapter 7 Solutions
ESSENTIALS OF GENETICS ALC & MOD MSTG/ET VP
Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 - CASE STUDY | Links to autism As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
HOW DO WE KNOW?
1. In this chapter, we focused on...Ch. 7 -
CONCEPT QUESTION
2. Review the Chapter Concepts...Ch. 7 - Describe the cytological observation that suggests...Ch. 7 - Why does more crossing over occur between two...Ch. 7 - Why is a 50 percent recovery of single-crossover...Ch. 7 - Why are double-crossover events expected less...
Ch. 7 - What is the proposed basis for positive...Ch. 7 - What three essential criteria must be met in order...Ch. 7 - The genes dumpy wings (dp), clot eyes (cl), and...Ch. 7 - Colored aleurone in the kernels of corn is due to...Ch. 7 - In the cross shown here, involving two linked...Ch. 7 - In a series of two-point map crosses involving...Ch. 7 -
13. Two different female Drosophila were...Ch. 7 -
14. In Drosophila, a cross was made between...Ch. 7 -
15. A cross in Drosophila involved the recessive,...Ch. 7 -
16. Drosophila melanogaster has one pair of sex...Ch. 7 -
17. Drosophila females homozygous for the third...Ch. 7 - In Drosophila, the two mutations Stubble bristles...Ch. 7 -
19. A female of genotype
produces 100 meiotic...Ch. 7 - In a plant, fruit color is either red or yellow,...Ch. 7 - In Drosophila, Dichaete (D) is a mutation on...Ch. 7 - An organism of the genotype AaBbCc was testcrossed...Ch. 7 - Based on our discussion of the potential...Ch. 7 - Prob. 24PDQCh. 7 - DNA markers have greatly enhanced the mapping of...Ch. 7 - Are sister chromatid exchanges effective in...
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- One of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y+, v+, and f+ (but not B+) was inverted with respect to the normal order of genes. This female was crossed to a wild-type male in the cross diagrammed her. The cross produced the following male offspring: Y v f B 48 y+ v+ f+ B+ 45 y v f B+ 11 y+ v+ f+ B 8 y v f B 1 y+ v+ f+ B+ 1 a. Why are there no male offspring with the allele combinations y v f+, v+ v+ f, y v+ f+, or y+ v f (regardless of the allele of the Bar eye gene)? b.What kinds of crossovers produced the y v f b+ and v+ y+ f+ B offspring? Can you determine any genetic distances from these classed of progeny? c. What kinds of crossovers produced the…arrow_forwardIn the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cMarrow_forwardIn Drosophila, Lyra (Ly) and stubble (Sb) are dominant mutations located at locus 40 and 58, on chromosome 3. A recessive mutation with bright eyes was discovered and shown also to be on chromosome 3. A map was obtained by crossing a female who was heterozygous for all three mutations to a male homozygous for the bright red mutation (temporarily will be called br). The following data were obtained. Ly Sb br 404 + + br 2 Ly + br 75 + Sb + 59 Ly + + 18 + Sb br 16 Ly Sb + 4 + + + 422 Diagram the cross and determine the location of the bright red mutation on chromosome 3arrow_forward
- Sepia eyes, spineless bristles, and striped body are three recessive mutations in Drosophila found on chromosome 3. A genetics student crosses a fly homozygous for the alleles encoding sepia eyes, spineless bristles, and striped body with a fly homozygous for the wild-type alleles—encoding red eyes, normal bristles, and solid body. The female progeny are then test-crossed with males that have sepia eyes, spineless bristles, and striped body. Assume that the interference between these genes is 0.2 and that 400 progeny flies are produced by the testcross. Based on the map distances provided in Figure , predict the phenotypes and proportions of the progeny resulting from the test cross.arrow_forwardIn Drosophila, Dichaete (D) is a mutation on chromosome III witha dominant effect on wing shape. It is lethal when homozygous.The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny with a Dichaete phenotype were backcrossed to the ebony, pink homozygotes. Question: a.) Using the results of this backcross shown in the following table, diagram the cross, showing the genotypes of the parents and offspring of both crosses. b.) What is the sequence and interlocus distance between thesethree genes? Phenotype NumberDichaete 401ebony, pink 389Dichaete, ebony 84pink 96Dichaete, pink 2ebony 3Dichaete, ebony, pink 12wild type 13arrow_forwardIn the fruit fly Drosophila melanogaster, the trait of black body is due to a gene on chromosome 2 and black body b is recessive to wild type body b + . The trait of purple eyes is controlled by a gene that is also on chromosome 2 and purple eyes p is recessive to wild type eyes p + . A true-breeding wild type strain is crossed with a true breeding strain that has black bodies and purple eyes. The F1 generation is then testcrossed to the black body, purple eye strain and 500 progeny are produced as follows: 224 wild type for both body and eye 236 black body and purple eye 18 wild type body and purple eye 22 black body and wild type eye. What is the recombination frequency and genetic map distance between the two genes?arrow_forward
- In Drosophila, the vermilion eye color is determined by a recessive allele, v, of an X-linked gene. The wildtype color is determined by the v+ allele and causes a brick red eye color. In a cross of a heterozygous female with a wild type male you observe 340 red eye females, 136 red eye males, and 90 vermillion males. Do these results follow your expectations?arrow_forwardThe mutant genes for vestigial wings and singed bristles are approximately 30 map units apart on chromosome II in Drosophila. Assume that a vestigial-winged female was mated to a singed-bristle male, and that the resulting F1 phenotypically wild type females were mated to vestigial singed males. Of 1000 offspring, which phenotype class would represent the product of crossing over between the genes, and how many would you expect? a) vestigial, 300 flies b) vestigial, 150 flies wild type, 300 flies d) singed, 150 flies e) vestigial, singed double mutants, 150 fliesarrow_forwardFemale Drosophila heterozygous for three recessive mutations e (ebony body), st (scarlet eyes), and ss (spineless bristles) were testcrossed, and the following progeny were obtained: Phenotype Number wild-type 67 ebony 8 ebony, scarlet 68 ebony, spineless 347 ebony, scarlet, spineless 78 scarlet 368 scarlet, spineless 10 spineless 54 (a) What indicates that the genes are linked? (b) What was the genotype of the original heterozygous females? (c) What is the order of the genes? (d) What is the map distance between e and st? (e) Between e and ss? (f) What is the coefficient of coincidence? (g) Diagram the crosses in this experiment.arrow_forward
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