SHIGLEY'S MECH.ENGR...(LL)-PKG.>CUSTOM<
SHIGLEY'S MECH.ENGR...(LL)-PKG.>CUSTOM<
10th Edition
ISBN: 9781260028379
Author: BUDYNAS
Publisher: MCG/CREATE
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Chapter 7, Problem 33P

A transverse drilled and reamed hole can be used in a solid shaft to hold a pin that locates and holds a mechanical element, such as the hub of a gear, in axial position, and allows for the transmission of torque. Since a small-diameter hole introduces high stress concentration, and a larger diameter hole erodes the area resisting bending and torsion, investigate the existence of a pin diameter with minimum adverse affect on the shaft. Specifically, determine the pin diameter, as a percentage of the shaft diameter, that minimizes the peak stress in the shaft. (Hint: Use Table A–16.)

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As part of an innovation policy introduced within the company to research into newer design of swings, the R and D department is proposing that work should be carried out on motorized swings. The initial consideration is to use an electric motor to spin the central shaft. For this purpose a hollow shaft of diameter ratio 3:5 is required to transmit 600 kW at 110 rpm, the maximum torque being 12% greater than the mean. The shear stress is not to exceed 60MPa and the twist in a length of 3m is not to exceed 1 Degree (1º). Calculate the minimum outer diameter (D) to satisfy both these conditions. Take G = 80GN/m2
As part of an innovation policy introduced within the company to research into newer design of swings, the R and D department is proposing that work should be carried out on motorized swings. The initial consideration is to use an electric motor to spin the central shaft. For this purpose a hollow shaft of diameter ratio 3:5 is required to transmit 600 kW at 110 rpm, the maximum torque being 12% greater than the mean. The shear stress is not to exceed 60MPa and the twist in a length of 3m is not to exceed 1 Degree (1º). Calculate the minimum outer diameter (D) to satisfy both these conditions. Take G = 80GN/m2      Complete using torsion equation and polar second moment of area equation.
In drilling a deep oil well the drill shaft, consisting of sections of “drill rod”, is powered from the top, while the load or counter torque is taken off at the bottom. The drill hole is 3 1/2 miles deep. Assuming a solid drill rod of circular cross section and 1 in. diameter, designed to a working shear stress of 5,000 psi, turning at 700 rpm, calculate (a) The wind-up, i.e. the twist angle between the top and bottom. (b) The horsepower of the driving motor. (c) State all assumptions, and comment on the results. What other considerations may have to be taken into account in using this drill? NOTE: The shear modulus of steel may be taken as 12 x 106 psi. Also 1 mile = 5,280 ft.
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