Interpretation:
The reason for a deuterium-labelled compound to produce only
Concept Introduction:
Electrophiles are electron deficient species which has positive or partially positive charge. Lewis acids are electrophiles which accept electron pair.
Nucleophiles are electron rich species which has negative or partially negative charge. Lewis bases are nucleophiles which donate electron pair.
Free radical is an atom, molecule or ion that has unpaired electrons which makes it highly chemically reactive.
Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a
Elimination reaction: A reaction in which two substituent groups are detached and a double bond is formed is called elimination reaction.
Addition reaction: It is the reaction in which unsaturated bonds are converted to saturated molecules by the addition of molecules.
Elimination bimolecular mechanism
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EBK ORGANIC CHEMISTRY
- Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H15l products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. наarrow_forwardThe electrophilic addition of HBr to 3-cyclohexylbut-1-ene gives a mixture of two constitutional isomers. These two isomers can also be produced from 3-cylcohexybut-2-ene, but one of which requires different reaction conditions; the electrophilic addition of HBr to 3-cylcohexybut-2-ene produces one of these isomers while the electrophilic addition of HBr to 3-cylcohexybut-2-ene, in the presence of peroxides, produces the other one. Draw the structure for the isomer product that can result from the reactants 3-cyclohexylbut-1-ene and 3-cylcohexybut-2-ene using different reaction conditions. Part 1 of 2 Click and drag to start drawing a structure. C 8 DY 000 8: >arrow_forward1.Treatment of 3-methyl-2-butanol with hydrogen chloride yielded only a trace amount of 2-chloro-3-methylbutane. An isomeric chloride was isolated in 97% yield. Explain why an isomeric compound is formed instead, andsuggest a reasonable structure for this product. 2) Acid-catalyzed hydration of 2-Methyl-1-butene yields two alcohols. The major product does not undergo oxidation, while the minor product will undergo oxidation. Explain why, by showing the structures of the products. 3) The Williamson ether synthesis cannot be used to prepare tert-butyl phenyl ether. Explain why this method cannot be used in this case. 4) Show the structure of the main product when 2,2-dimethyloxirane reacts in methanol. (a) in the presence of an acid, (b) with added sodium methoxide.arrow_forward
- Identify two alkenes that react with HBr to form 1-bromo-1-methylcyclohexane without undergoing a carbocation rearrangement.arrow_forwardCompound A reacts with one equivalent of H₂ in the presence of a catalyst to give methylcyclohexane. Compound A can be formed upon treatment of 1-bromo-1-methylcyclohexane with sodium methoxide. What is the structure of compound A? [ Draw Your Solutionarrow_forwardWhich of these alkyl chlorides undergoes dehydrohalogenation in the presence of a strong base to give pent-2-ene (shown below) as the only alkene product? O l-chloro-2-methylbutane O 2-chloropentane O 3-chloropentane O 1-chloropentane O l-chloro-3-methylbutanearrow_forward
- Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products. Explain why A is the major product despite the fact that it contains the less substituted double bond.arrow_forwardWhich alkene reacts with a red-brown solution of bromine to form 1,2-dibromo-1-ethylcyclohexane.arrow_forwardWhen 2-iodo-1,4-dimethylcyclohexane is heated in acetic acid, CH3COOH, a mixture of substitution and elimination products is obtained. Provide structures for all possible products, writing [not drawing] the name of the mechanism by which each one is formed.arrow_forward
- Addition of HBr to allene (CH2 = C = CH2) forms 2-bromoprop-1-ene rather than 3-bromoprop-1-ene, even though 3-bromoprop-1-ene is formed from an allylic carbocation. Considering the arrangement of orbitals in the allene reactant, explain this result.arrow_forwardDraw an approximate reaction-energy diagram showing the curves for the two possible pathways for ionic addition of HBr to 1-methylcyclohexene. (a) Formation of the major product, 1-bromo-1-methylcyclohexane, and (b) formation of the minor product, 1-bromo-2-methylcyclohexane. Point out how these curves show that 1-bromo-1-methylcyclohexane should be formed fasterarrow_forwardReaction of HBr with 3-methylcyclohexene yields a mixture of four products: cis-and trans-1-bromo-3-methylcyclohexane and cis-and trans-1-bromo-2-methylcyclohexane. The analogous reaction of HBr with 3-bromocyclohexene yields trans-1, 2-dibromocyclohexane as the soleproduct. Draw structures of the possible intermediates, and then explain why only a single product is formed in this reaction.arrow_forward
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