(a)
Stream velocity
Answer to Problem 7.43P
The stream velocity is 34 m/s.
Explanation of Solution
Given Information:
We have following figure:
And at
Calculation:
Let’s calculate Reynolds’s number,
And the coefficient of friction:
- The shear stress is given as:
So, the stream velocity is 34 m/s.
Conclusion:
The stream velocity is 34 m/s.
(b)
The boundary layer thickness,
Answer to Problem 7.43P
The boundary layer thickness is 36 mm.
Explanation of Solution
Given Information:
We have following figure
And at
Calculation:
Let’s calculate Reynolds’s number,
And the coefficient of friction:
The shear stress is given as:
So, the stream velocity is 34 m/s.
Using this velocity, we can now, evaluate Reynolds’s number as below:
Let’s calculate the boundary layer thickness,
So, the boundary layer thickness is 36 mm.
Conclusion:
The boundary layer thickness is 36 mm.
(c)
Velocity,
Answer to Problem 7.43P
The velocity at 5 cm above the element is 34 m/s.
Explanation of Solution
Given Information:
We have following figure
And at
Calculation:
Let’s calculate Reynolds’s number,
And the coefficient of friction,
The shear stress is given as,
So the stream velocity is 34 m/s.
Using this velocity, we can now, evaluate Reynolds’s number as below,
Let’s calculate the boundary layer thickness,
So the boundary layer thickness is 36 mm.
Boundary layer velocity at 5 cm above the element will be equal to stream velocity which is 34 m/s because this point is well above the boundary layer thickness.
Conclusion:
The velocity at 5 cm above the element is 34 m/s.
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Chapter 7 Solutions
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