(a)
Interpretation:
The total energy output must be calculated for the blackbody heated at 4500 K.
Concept introduction:
Stefan’s law essentially states that the total quantity of heat energy released by a perfect blackbody per unit area per second is directly proportional to the absolute temperature’s fourth power of its surface given by the equation-
Wein’s displacement Law which states that the maximum wavelength in micrometers for the radiations of the blackbody is given by:
Where,
T = temperature in Kelvin
Answer to Problem 7.4QAP
The amount of energy emitted by Et at temperature 4500K is
Explanation of Solution
The total energy Et emitted per unit time per unit area is calculated by:
Given that-
T = 4500K
The value of total energy Et is:
Thus, the total amount of energy emitted Et at 4500 K is
(b)
Interpretation:
The total energy output must be calculated for the blackbody heated at 2500 K.
Concept introduction:
Stefan’s law essentially states that the total quantity of heat energy released by a perfect blackbody per unit area per second is directly proportional to the absolute temperature’s fourth power of its surface given by the equation-
Wein’s displacement Law which states that the maximum wavelength in micrometers for the radiations of the blackbody is given by:
Where,
T = temperature in Kelvin
Answer to Problem 7.4QAP
The amount of energy emitted by Et at temperature 2500K is
Explanation of Solution
The total energy Et emitted per unit time per unit area is calculated by:
Given that-
T = 2500K
The value of total energy Et is:
Thus, the total amount of energy emitted Et at 2500 K is
(c)
Interpretation:
The total energy output must be calculated for the blackbody heated at 1250K.
Concept introduction:
Stefan’s law essentially states that the total quantity of heat energy released by a perfect blackbody per unit area per second is directly proportional to the absolute temperature’s fourth power of its surface given by the equation-
Wein’s displacement Law which states that the maximum wavelength in micrometers for the radiations of the blackbody is given by:
Where,
T = temperature in Kelvin
Answer to Problem 7.4QAP
The amount of energy emitted by Et at temperature 1250K is
Explanation of Solution
The total energy Et emitted per unit time per unit area is calculated by:
Given that-
T = 1250K
The value of total energy Et is:
Thus, the total amount of energy emitted Et at 1250 K is
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Chapter 7 Solutions
Principles of Instrumental Analysis
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