All-Access Pack - Physics 10e Set
1st Edition
ISBN: 9781118718377
Author: Halliday
Publisher: John Wiley & Sons Inc (US)
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Textbook Question
Chapter 7, Problem 76P
A 45 kg block of ice slides down a frictionless incline 1.5 m long and 0.91 m high. A worker pushes up against the ice, parallel to the incline, so that the block slides down at constant speed. (a) Find the magnitude of the worker’s force. How much work is done on the block by (b) the worker’s force, (c) the gravitational force on the block, (d) the normal force on the block from the surface of the incline, and (e) the net force on the block?
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All-Access Pack - Physics 10e Set
Ch. 7 - Rank the following velocities according to the...Ch. 7 - Figure 7-16a shows two horizontal forces that act...Ch. 7 - Is positive or negative work done by a constant...Ch. 7 - In three situations, a briefly applied horizontal...Ch. 7 - The graphs in Fig. 7-18 give the x component Fx of...Ch. 7 - Figure 7-19 gives the x component Fx of a force...Ch. 7 - In Fig. 7-20, a greased pig has a choice of three...Ch. 7 - Figure 7-21a shows four situations in which a...Ch. 7 - Spring A is stiffer than spring B kA kB. The...Ch. 7 - A glob of slime is launched or dropped from the...
Ch. 7 - In three situations, a single force acts on a...Ch. 7 - Figure 7-23 shows three arrangements of a block...Ch. 7 - SSM A proton mass m = 1.67 1027 kg is being...Ch. 7 - If a Saturn V rocket with an Apollo spacecraft...Ch. 7 - On August 10, 1972, a large meteorite skipped...Ch. 7 - An explosion at ground level leaves a crater with...Ch. 7 - A father racing his son has half the kinetic...Ch. 7 - A bead with mass 1.8 10-2 kg is moving along a...Ch. 7 - A 3.0 kg body is at rest on a frictionless...Ch. 7 - A ice block floating in a river is pushed through...Ch. 7 - The only force acting on a 2.0 kg canister that is...Ch. 7 - A coin slides over a frictionless plane and across...Ch. 7 - A 12.0 N force with a fixed orientation does work...Ch. 7 - A can of bolts and nuts is pushed 2.00 m along an...Ch. 7 - A luge and its rider, with a total mass of 85 kg,...Ch. 7 - 14 GO Figure 7-27 shows an overhead view of three...Ch. 7 - GO Figure 7-28 shows three forces applied to a...Ch. 7 - GO An 8.0 kg object is moving in the positive...Ch. 7 - SSM WWW A helicopter lifts a 72 kg astronaut 15 m...Ch. 7 - a In 1975 the roof of Montreals Velodrome, witha...Ch. 7 - GO In Fig. 7-30, a block of ice slides down a...Ch. 7 - A block is sent up a frictionless ramp along which...Ch. 7 - 21 SSM A cord is used to vertically lower an...Ch. 7 - A cave rescue team lifts an injured spelunker...Ch. 7 - In Fig. 7-32, a constant force Fa of magnitude...Ch. 7 - GO In Fig. 7-33, a horizontal force Fa of...Ch. 7 - GO In Fig. 7-34, a 0.250 kg block of cheese lies...Ch. 7 - In Fig. 7-10, we must apply a force of magnitude...Ch. 7 - A spring and block are in the arrangement of Fig....Ch. 7 - During spring semester at MIT, residents of the...Ch. 7 - In the arrangement of Fig. 7-10, we gradually pull...Ch. 7 - In Fig. 7-10a, a block of mass m lies on a...Ch. 7 - SSM WWW The only force acting on a 2.0 kg body as...Ch. 7 - Figure 7-37 gives spring force Fx versus position...Ch. 7 - GO The block in Fig. 7-10a lies on a horizontal...Ch. 7 - ILW A 10 kg brick moves along an xaxis. Its...Ch. 7 - SSM WWW The force on a particle is directed along...Ch. 7 - GO A 5.0 kg block moves in a straight line on a...Ch. 7 - GO Figure 7-40 gives the acceleration of a 2.00 kg...Ch. 7 - A 1.5 kg block is initially at rest on a...Ch. 7 - GO A force F= cx3.00x2iacts on a particle as the...Ch. 7 - A can of sardines is made to move along an xaxis...Ch. 7 - A single force acts on a 3.0 kg particle-like...Ch. 7 - GO Figure 7-41 shows a cord attached to a cart...Ch. 7 - SSM A force of 5.0 N acts on a 15 kg body...Ch. 7 - A skier is pulled by a towrope up a frictionless...Ch. 7 - SSM ILW A 100 kg block is pulled at a constant...Ch. 7 - The loaded cab of an elevator has a mass of 3.0 ...Ch. 7 - A machine carries a 4.0 kg package from an initial...Ch. 7 - A 0.30 kg ladle sliding on a horizontal...Ch. 7 - Prob. 49PCh. 7 - a At a certain instant, a particle-like object is...Ch. 7 - A force F= 3.00 N i 7.00 N j 7.00 N k acts on...Ch. 7 - A funny car accelerates from rest through a...Ch. 7 - Figure 7-42 shows a cold package of hot dogs...Ch. 7 - GO The only force acting on a 2.0 kg body as the...Ch. 7 - SSM A horse pulls a cart with a force of 40 lb at...Ch. 7 - An initially stationary 2.0 kg object accelerates...Ch. 7 - A 230 kg crate hangs from the end of a rope of...Ch. 7 - To pull a 50 kg crate across a horizontal...Ch. 7 - A force Fa is applied to a bead as the bead is...Ch. 7 - A frightened child is restrained by her mother as...Ch. 7 - How much work is done by a force F= 2x N i 3 N j,...Ch. 7 - A 250 g block is dropped onto a relaxed vertical...Ch. 7 - 63 SSM To push a 25.0 kg crate up a frictionless...Ch. 7 - Boxes are transported from one location to another...Ch. 7 - In Fig. 7-47, a cord runs around two massless,...Ch. 7 - If a car of mass 1200 kg is moving along a highway...Ch. 7 - SSM A spring with a pointer attached is hanging...Ch. 7 - An iceboat is at rest on a frictionless frozen...Ch. 7 - If a ski lift raises 100 passengers averaging 660...Ch. 7 - A force F= 4.0 N i cj acts on a particle as the...Ch. 7 - A constant force of magnitude 10 N makes an angle...Ch. 7 - In Fig. 7-49a, a 2.0 N force is applied to a 4.0...Ch. 7 - A force F in the positive direction of an x axis...Ch. 7 - A particle moves along a straight path through...Ch. 7 - SSM What is the power of the force required to...Ch. 7 - A 45 kg block of ice slides down a frictionless...Ch. 7 - As a particle moves along an x axis, a force in...Ch. 7 - A CD case slides along a floor in the positive...Ch. 7 - SSM A 2.0 kg lunchbox is sent sliding over a...Ch. 7 - Numerical integration. A breadbox is made to move...Ch. 7 - In the block-spring arrangement of Fig. 7-10, the...Ch. 7 - A 4.00 kg block is pulled up a frictionless...Ch. 7 - A spring with a spring constant of 18.0 N/cm has a...Ch. 7 - A force F= 2.00 i 9.00 j 5.30 k N acts on a 2.90...Ch. 7 - At t = 0, force F= 5.00 i 5.00 j 4.00 k N begins...
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- A block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 25.0 below the horizontal as shown in Figure P6.3. Determine the work done on the block by (a) the applied force, (b) the normal force exerted by the table, (c) the gravitational force, and (d) the net force on the block. Figure P6.3arrow_forwardAs a young man, Tarzan climbed up a vine to reach his tree house. As he got older, he decided to build and use a staircase instead. Since the work of the gravitational force mg is path Independent, what did the King of the Apes gain in using stairs?arrow_forward(a) A force F=(4xi+3yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 5.00 m. Find the work W=Fdr done by the force on the object. (b) What If? Find the work W=Fdr done by the force on the object if it moves from the origin to (5.00 m, 5.00 m) along a straightline path making an angle of 45.0 with the positive x axis. Is the work done by this force dependent on the path taken between the initial and final points?arrow_forward
- Give an example of a situation in which there is a force and a displacement, but the force does no work. Explain why it does no work.arrow_forwardIn Figure 5.5 (a)-(d), a block moves to the right in the positive x-direction through the displacement x while under the influence of a force with the same magnitude F. Which of the following is the correct order of the amount of work done by the force F, from most positive to most negative? (a) d, c, a, b (b) c, a, b, d (c) c, a, d, barrow_forwardAn object of mass m = 5.8 kg moves under the influence of one force. That force causes the object to move along a path given by x = 6.0 + 5.0t + 2.0t2, where x is in meters and t is in seconds. Calculate the work done by the force on the object from t = 2.0 s to t = 7.0 s.arrow_forward
- Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 90.0 kg, down a 60.0° slope at constant speed, as shown in Figure 7.37. The coefficient of friction between the sled and the snow is 0.100. (a) How much work is done by friction as the sled moves 30.0 m along the hill? (b) How much work is done by the rope on the sled in this distance? (c) What is the work done by the gravitational force on the sled? (d) What is the total work done?arrow_forwardA shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 N frictional force. He pushes in a direction 25.0° below the horizontal. (a) What is the work done on the cart by friction? (b) What is the work done on the cart by the gravitational force? (c) What is the work done on the cart by the shopper? (d) Find the force the shopper exerts, using energy considerations. (e) What is the total work done on the cart?arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forward
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