INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN
INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN
8th Edition
ISBN: 9780134580289
Author: CORWIN
Publisher: PEARSON
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Chapter 7, Problem 77E
Interpretation Introduction

(a)

Interpretation:

The reaction HNO3(aq)+Ca(OH)2(aq) is to be completed and balanced.

Concept introduction:

The process in which the reactants combine to form a new product is called a chemical reaction. The chemical and physical properties of the products are different from those of the reactants. The different types of chemical reactions are combination reaction, decomposition reaction, and displacement reaction.

Expert Solution
Check Mark

Answer to Problem 77E

The reaction HNO3(aq)+Ca(OH)2(aq) is completed and balanced as shown below. 2HNO3(aq)+Ca(OH)2(aq)Ca(NO3)2(aq)+2H2O(l)

Explanation of Solution

The reaction of an acid with a base results in the formation of salt and water. This reaction is known as the neutralization reaction.

Therefore, the chemical equation for the reaction HNO3(aq)+Ca(OH)2(aq) is given below.

HNO3(aq)+Ca(OH)2(aq)Ca(NO3)2(aq)+H2O(l)

The numbers of atoms on either side of the equation are not the same. Therefore, the coefficient 2 is added before HNO3(aq) and H2O(l) to balance the equation. Therefore, the balanced equation is given below.

2HNO3(aq)+Ca(OH)2(aq)Ca(NO3)2(aq)+2H2O(l)

Conclusion

The reaction HNO3(aq)+Ca(OH)2(aq) is completed and balanced as shown below. 2HNO3(aq)+Ca(OH)2(aq)Ca(NO3)2(aq)+2H2O(l)

Interpretation Introduction

(b)

Interpretation:

The reaction HNO2(aq)+Ca(OH)2(aq) is to be completed and balanced.

Concept introduction:

The process in which the reactants combine to form a new product is called a chemical reaction. The chemical and physical properties of the products are different from those of the reactants. The different types of chemical reactions are combination reaction, decomposition reaction, and displacement reaction.

Expert Solution
Check Mark

Answer to Problem 77E

The reaction HNO2(aq)+Ca(OH)2(aq) is completed and balanced as shown below. 2HNO2(aq)+Ca(OH)2(aq)Ca(NO2)2(aq)+2H2O(l)

Explanation of Solution

The reaction of an acid with a base results in the formation of salt and water. This reaction is known as the neutralization reaction.

Therefore, the chemical equation for the reaction HNO2(aq)+Ca(OH)2(aq) is given below.

HNO2(aq)+Ca(OH)2(aq)Ca(NO2)2(aq)+H2O(l)

The numbers of atoms on either side of the equation are not the same. Therefore, the coefficient 2 is added before HNO2(aq) and H2O(l) to balance the equation. Therefore, the balanced equation is given below.

2HNO2(aq)+Ca(OH)2(aq)Ca(NO2)2(aq)+2H2O(l)

Conclusion

The reaction HNO2(aq)+Ca(OH)2(aq) is completed and balanced as shown below. 2HNO2(aq)+Ca(OH)2(aq)Ca(NO2)2(aq)+2H2O(l)

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Chapter 7 Solutions

INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN

Ch. 7 - Prob. 11CECh. 7 - Prob. 12CECh. 7 - Prob. 13CECh. 7 - Prob. 14CECh. 7 - Prob. 15CECh. 7 - Prob. 16CECh. 7 - Prob. 1KTCh. 7 - Prob. 2KTCh. 7 - Prob. 3KTCh. 7 - Prob. 4KTCh. 7 - Prob. 5KTCh. 7 - Prob. 6KTCh. 7 - Prob. 7KTCh. 7 - Prob. 8KTCh. 7 - Prob. 9KTCh. 7 - Prob. 10KTCh. 7 - Prob. 11KTCh. 7 - Prob. 12KTCh. 7 - Prob. 13KTCh. 7 - Prob. 14KTCh. 7 - Prob. 15KTCh. 7 - Prob. 16KTCh. 7 - Prob. 17KTCh. 7 - Prob. 18KTCh. 7 - Prob. 19KTCh. 7 - Prob. 20KTCh. 7 - Prob. 21KTCh. 7 - Prob. 22KTCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - Prob. 59ECh. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Prob. 66ECh. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Prob. 81ECh. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Prob. 86ECh. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 1STCh. 7 - Prob. 2STCh. 7 - Prob. 3STCh. 7 - Prob. 4STCh. 7 - Prob. 5STCh. 7 - Prob. 6STCh. 7 - Prob. 7STCh. 7 - Prob. 8STCh. 7 - Prob. 9STCh. 7 - Prob. 10STCh. 7 - Prob. 11STCh. 7 - Prob. 12STCh. 7 - Prob. 13STCh. 7 - Prob. 14STCh. 7 - Prob. 15STCh. 7 - Prob. 16STCh. 7 - Prob. 17STCh. 7 - Prob. 18ST
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