Vector A → has a magnitude of 5.00 units, and vector B → has a magnitude of 9.00 units. The two vectors make an angle of 50.0° with each other. Find A → ⋅ B → .
Vector A → has a magnitude of 5.00 units, and vector B → has a magnitude of 9.00 units. The two vectors make an angle of 50.0° with each other. Find A → ⋅ B → .
Solution Summary: The author calculates the dot product of two vectors stackrelto 'A and
Vector
A
→
has a magnitude of 5.00 units, and vector
B
→
has a magnitude of 9.00 units. The two vectors make an angle of 50.0° with each other. Find
A
→
⋅
B
→
.
What is the sum of the following four vectors in (a) unit-vector notation, and as (b) a magnitude and (c) an angle? Positive angles are counterclockwise from the positive direction of the x axis; negative angles are clockwise.
A→=(2.00m)î+(3.00m)ĵB→ = 4.00 m, at 65.0°C→=(-4.00m)î-(6.00m)ĵD→ = 5.00 m, at -235°
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Consider the two vectors shown below. The two vectors have magnitudes of IAI=20|A→|=20 and |BI=18|B→|=18. The small angles the two vectors make with the x-axis are TETA ?=16?θA=16o and TETA B=24oθB=24o. Determine the magnitude of the vector |C||C→| given by:
C = 3A - 2B
Please express your answer using zero decimal place.
Vectors A→A→ and B→B→ both have a magnitude of 8. If their resultant has a magnitude of 10, what is the angle between them?
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