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Interpretation:
The reason for anti-coplanar transition state of ethyl bromide being more favored over syn coplanar is to be explained by showing the Newman projection formulas.
Concept introduction:
Staggered conformation: It is the arrangement of atoms or groups of atoms in a molecule resulting in a
Eclipsed conformation: It is the arrangement of atoms or groups of atoms in a molecule resulting in a
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Chapter 7 Solutions
Organic Chemistry, 12e Study Guide/Student Solutions Manual
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1- phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Whichproduct predominates—the product of inversion or the product of retention of conguration? (c) Suggest an explanation for this phenomenon.arrow_forwardThe alkene shown undergoes bromination. (a) Draw the product(s) of bromination of this compound, including all expected stereoisomers (if any). Use wedge‑and‑dash bonds to designate the stereochemistry at any chirality centers, and make sure to draw an explicit hydrogen if a chirality center has one. (b) Characterize the starting alkene as having the E or Z configuration. (c) characterize the product(s).arrow_forwardPRACTICE PROBLEM 8.20 Specify the alkene and reagents needed to synthesize each of the following diols. OH HO- (a) (b) (c) HO. н он HO (racemic) (racemic)arrow_forward
- (a) Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.(b) Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?(c) Draw resonance forms to show the charge distribution on the pyrrole structure.arrow_forward6.2 (-)-Cameroonanol has been isolated from the essential oil of Echinops giganteus (globe thistle) plants and it is associated with a strong woody fragrance. Its structure, includ- ing relative stereochemistry, was confirmed when it was made in the laboratory according to the sequence shown below.' Recall that a C=C bond is made up of one o bond and one 7 bond. These two bonds together have a combined BDE (bond dissociation energy) of 607 kJ/mol. Use this information to estimate the AH° for the conversion of compound 1 into compound 2. Br two steps H.. H HBr hv H (-Cameroonanolarrow_forwardIn some nucleophilic substitutions under SN1 conditions, completeracemization does not occur and a small excess of one enantiomer ispresent. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data.(b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forward
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forwardIn some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer ispresent. For example, treatment of optically pure 1-bromo-1phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forwardIn some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenyl-1-propanol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates-the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon. H Br он H20 1-bromo-1-phenylpropane 1-phenyl-1-propanol observed [a) = +5.0 optically pure S isomer, [a] =-48 %3Darrow_forward
- The following molecular model of a dimethyl-substituted biphenyl represents the lowest-energy conformation of the molecule. Why are the two benzene rings tilted at a 63� angle to each other rather than being in the same plane so that their p orbitals overlap? Why doesn't complete rotation around the single bond joining the two rings occur?arrow_forward(a) H. H. 6.44 Which of the following reactions will yield a racemic mixture of products? HCI HBr (a) (c) H2 H2 (b) (d) Pt Ptarrow_forwardArrange the following in increasing order of stability:arrow_forward
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