EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
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Question
Chapter 7, Problem P15P
Program Plan Intro
Care-of-address:
- A temporary IP address for a mobile device is a care-of-address (COA). It will enable message delivery when the mobile device is connecting from some other network other than home network.
- The current position of the mobile node in the Internet is identifies by the COA and makes it possible to connect from the different position without changing the device home address.
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Students have asked these similar questions
Consider two mobile nodes in a foreign network having a foreign
agent. Is it possible for the two mobile nodes to use the same
care-of address in mobile IP? Explain your answer.
A host on your network is said to have a static IP address if it offers a service that requires the server to always use the same IP address. This kind of IP address can only be used once. In the event when a certain IP address has to be assigned manually, which IP addressing technique is considered to be the most effective? Why is this the case, exactly?
A simple CIDR routing table is shown in Figure 1. For each of the destination IP addresses below, indicate which entry in the table it matches. Indicating none if no routing entry can be matched (hint: given an IP packet, the router will check whether there is a routing entry which can be used to route this packet, by checking the destination IP address in the packet with each routing entry: based on the subnet mask of each routing entry, it can extract the network ID and compare it with each routing entry; if there are a few routing entries which can match, the entry with the longest subnet mask wins).
Address Mask
Output Port
10.19.0.0/16
1
10.19.128/17
2
10.19.192/18
3
10.19.192/19
4
0.0.0.0/1
5
141.219.2.10
10.10.10.10
10.19.86.141
10.19.193.6
10.19.255.86
10.19.192.18
Chapter 7 Solutions
EBK COMPUTER NETWORKING
Ch. 7 - Prob. R1RQCh. 7 - Prob. R2RQCh. 7 - Prob. R3RQCh. 7 - Prob. R4RQCh. 7 - Prob. R5RQCh. 7 - Prob. R6RQCh. 7 - Prob. R7RQCh. 7 - Prob. R8RQCh. 7 - Prob. R9RQCh. 7 - Prob. R10RQ
Ch. 7 - Prob. R11RQCh. 7 - Prob. R12RQCh. 7 - Prob. R13RQCh. 7 - Prob. R14RQCh. 7 - Prob. R15RQCh. 7 - Prob. R16RQCh. 7 - Prob. R17RQCh. 7 - Prob. R18RQCh. 7 - Prob. R19RQCh. 7 - Prob. R20RQCh. 7 - Prob. R21RQCh. 7 - Prob. R22RQCh. 7 - Prob. R23RQCh. 7 - Prob. P1PCh. 7 - Prob. P2PCh. 7 - Prob. P3PCh. 7 - Prob. P5PCh. 7 - Prob. P6PCh. 7 - Prob. P7PCh. 7 - Prob. P8PCh. 7 - Prob. P10PCh. 7 - Prob. P11PCh. 7 - Prob. P12PCh. 7 - Prob. P13PCh. 7 - Prob. P14PCh. 7 - Prob. P15PCh. 7 - Prob. P16P
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Similar questions
- For each subnet assign a private IP address (of the form a.b.c.d/y) such that:• The IP range is contained within 10.0.0.0/24.• The number of wasted IP address in each subnet is minimized.• The Forwarding table in the central router is minimized. Once IP address for each subnet are assigned, provide the forwarding table for the centralrouter. IN THE details PLZ ...arrow_forwardIn newer implementations, repeat ARP queries about a timed out entry are first sent unicast, in order to reduce broadcast traffic. What would have to happen to create a situation where the repeated unicast query for a given IP address fails, but a follow-up broadcast query for that same IP address succeeds?arrow_forwardThe TTL behaviour for IP-to-Label or Label-to-IP connections is depicted in the below image. Ingress LSR receives a packet with a TTL value of 289 arriving. What would the TTL value be for the ingress and egress LSRs? the letters (A, B, C, D, E, F, G, and H). TTL = 289 MPLS Label IPv4 Packet Ingress LSR TTL = A: TTL = B: LSR TTL= C: TTL=D: X LSR TTL=E: TTL=F: Label Switched wh TTL= G: LSR TTL=H: Egress LSRarrow_forward
- How does the "prefix delegation" mechanism function in IPv6 subnetting, and how does it differ from IPv4 subnetting techniques?arrow_forwardA TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overload. Assume that IP overhead per packet is 26 bytes. What is the total IP overhead (in bytes) in the network for this transmission?arrow_forwardA TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. what is the total IP overhead in the second network for this transmission.arrow_forward
- In wireless communication, the Mobile Subscriber (MS) has shared a secret key. A-Key with HLR during registration. In roaming, in order to enable VLR to authenticate MS, HLR can just transfer A-Key to VLR directly. Explain why most standard protocol did not adopt this solution.arrow_forwardConsider an IPv4 network, each host can generate packet with a rate of 500 packet per second. If each host in network is identified by unique identification number 48 bits, then the host wrap around time for generating packet will be. (in sec).arrow_forwardYou could provide a static IP address to a host on your network when the service that host provides must always originate from the same server. In this case, the address would not change. I need to manually assign an IP address; which approach is the most effective way to do this? How did it get to be this way, and what factors contributed to it?arrow_forward
- Consider an IP datagram being sent from node A to node C. Please answer parts D, E, F.arrow_forwardARP only allows a single network to resolve addresses. Could ARP use an IP datagram to submit a request to and get a response from a distant server?arrow_forwardProvide short answers to the following: How do you determine whether an IP address is a multicast address? What is the TTL field in the IP header used for? What is the maximum length of options bytes that can be carried in an IPv4 header? Why do we have to multiply the offset field of an IP datagram by eight to obtain the real offset for the first byte of the datagram?arrow_forward
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