   Chapter 7.1, Problem 38E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding the Equation of a Sphere In Exercises 29-38, find the standard equation of the sphere with the given characteristics. See Examples 4 and 5.Center: (1, 2, 0); tangent to the yz-plane

To determine

To calculate: The standard equation of sphere if the centre of sphere is (1,2,0) and tangent to the yz-plane.

Explanation

Given Information:

The centre of sphere is (1,2,0) and tangent to the yz-plane.

Formula used:

The standard equation of a sphere with centre at (h,k,j) and radius r is,

(xh)2+(yk)2+(zj)2=r2

Calculation:

The sphere has tangent to the yz-plane that means circumference of the sphere touches perpendicularly at a single point of yz-plane. The centre of the sphere is (1,2,0), which is one unit in front of the yz-plane.

The distance between the circumference of the sphere to centre of the sphere is known as radius of the sphere.

So, the radius of the sphere is 1 because the distance from yz-plane to centre of the sphere is 1 unit

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