Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
4th Edition
ISBN: 9780133178579
Author: Ross L. Finney
Publisher: PEARSON
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Chapter 7.5, Problem 38E

a.

To determine

To find a curve to model the data and superimpose it on a scatter plot of population against tears after 1950.

a.

Expert Solution
Check Mark

Answer to Problem 38E

The curve is,

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  1

Explanation of Solution

Given information: Data

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  2

Calculation: The curve is,

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  3

  P=4593101+18e0.11t

b.

To determine

To find what number will the Virginia Beach population approach in the long run?

b.

Expert Solution
Check Mark

Answer to Problem 38E

The Virginia Beach population is 459310.

Explanation of Solution

Given information: Data

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  4

Calculation: The Virginia Beach population is obtained as,

  P=4593101+18e0.11t  =459310

Hence, the Virginia Beach population is 459310.

c.

To determine

To find when would the Virginia Beach population first exceed 450,000 people?

c.

Expert Solution
Check Mark

Answer to Problem 38E

In 2010 the Virginia Beach population first exceed 450,000 people.

Explanation of Solution

Given information: Data

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  5

Calculation: The required solution is obtained as,

  450000=4593101+18e0.11t          t=60

that is 2010.

Hence, In 2010 the Virginia Beach population first exceed 450,000 people.

d.

To determine

To write a logistic differential equation in the form dP/dt=kP(MP) .

d.

Expert Solution
Check Mark

Answer to Problem 38E

The required solution is dPdt=0.11P(459310P) .

Explanation of Solution

Given information:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  6

Calculation: The required solution is obtained as,

Using the long-term carrying capacity from part (b) and the growth rate from the logistic regression in part (a), we plug those into the logistic differential equation to find:

  dPdt=0.11P(459310P)

Hence, the required solution is dPdt=0.11P(459310P) .

e.

To determine

To write a logistic differential equation in the form dP/dt=kP(MP) .

e.

Expert Solution
Check Mark

Answer to Problem 38E

The required solution is dPdt=0.11P(459310P) .

Explanation of Solution

Given information:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 7.5, Problem 38E , additional homework tip  7

Calculation: The required solution is obtained as,

Using the long-term carrying capacity from part (b) and the growth rate from the logistic regression in part (a), we plug those into the logistic differential equation to find:

  dPdt=0.11P(459310P)

Hence, the required solution is dPdt=0.11P(459310P) .

Chapter 7 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 7.1 - Prob. 11QRCh. 7.1 - Prob. 12QRCh. 7.1 - Prob. 1ECh. 7.1 - Prob. 2ECh. 7.1 - Prob. 3ECh. 7.1 - Prob. 4ECh. 7.1 - Prob. 5ECh. 7.1 - Prob. 6ECh. 7.1 - Prob. 7ECh. 7.1 - Prob. 8ECh. 7.1 - Prob. 9ECh. 7.1 - Prob. 10ECh. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.1 - Prob. 48ECh. 7.1 - Prob. 49ECh. 7.1 - Prob. 50ECh. 7.1 - Prob. 51ECh. 7.1 - Prob. 52ECh. 7.1 - Prob. 53ECh. 7.1 - Prob. 54ECh. 7.1 - Prob. 55ECh. 7.1 - Prob. 56ECh. 7.1 - Prob. 57ECh. 7.1 - Prob. 58ECh. 7.1 - Prob. 59ECh. 7.1 - Prob. 60ECh. 7.1 - Prob. 61ECh. 7.1 - Prob. 62ECh. 7.1 - Prob. 63ECh. 7.1 - Prob. 64ECh. 7.1 - Prob. 65ECh. 7.1 - Prob. 66ECh. 7.1 - Prob. 67ECh. 7.1 - Prob. 68ECh. 7.1 - Prob. 69ECh. 7.1 - Prob. 70ECh. 7.1 - Prob. 71ECh. 7.1 - Prob. 72ECh. 7.1 - Prob. 73ECh. 7.1 - Prob. 74ECh. 7.1 - Prob. 75ECh. 7.1 - Prob. 76ECh. 7.1 - Prob. 77ECh. 7.1 - Prob. 78ECh. 7.1 - Prob. 79ECh. 7.1 - Prob. 80ECh. 7.2 - Prob. 1QRCh. 7.2 - Prob. 2QRCh. 7.2 - Prob. 3QRCh. 7.2 - Prob. 4QRCh. 7.2 - Prob. 5QRCh. 7.2 - Prob. 6QRCh. 7.2 - Prob. 7QRCh. 7.2 - Prob. 8QRCh. 7.2 - Prob. 9QRCh. 7.2 - Prob. 10QRCh. 7.2 - Prob. 1ECh. 7.2 - Prob. 2ECh. 7.2 - Prob. 3ECh. 7.2 - Prob. 4ECh. 7.2 - Prob. 5ECh. 7.2 - Prob. 6ECh. 7.2 - Prob. 7ECh. 7.2 - Prob. 8ECh. 7.2 - Prob. 9ECh. 7.2 - Prob. 10ECh. 7.2 - Prob. 11ECh. 7.2 - Prob. 12ECh. 7.2 - Prob. 13ECh. 7.2 - Prob. 14ECh. 7.2 - Prob. 15ECh. 7.2 - 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