OPERATIONS MANAGEMENT W/ CNCT+
12th Edition
ISBN: 9781259574931
Author: Stevenson
Publisher: MCG CUSTOM
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Chapter 7.S, Problem 19P
Summary Introduction
To estimate: The time needed to complete fifth unit of the job.
Introduction: Learning curve is referred as the cost curve, experience curve, efficiency curve or productivity curve. The leaving curve gives information about the cost, efficiency, productivity and performance of an organization.
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The fifth unit of a 25-unit job took 14.5 hours to complete. If a 90 percent learning curve is appropriate:a. How long should it take to complete the last unit?b. How long should it take to complete the 10th unit?c. Estimate the average time per unit for the 25 units.
A manager wants to estimate the remaining time that will be needed to complete a five-unit job. The initial unit of the job required 12 hours, and the work has a learning percentage of 77. Estimate the total time remaining to complete the job.
The 4th unit of a 10-unit job took seven hours to complete. The 6th unit has been worked on for two hours, but is not yet finished. Estimate the additional amount of time needed to finish the 6th unit if the work has a 65% learning curve slope
O a. 6.143 hours
O b. 5.114 hours
O c. 3.441 hours
O d. 3.058 hours
O e. 4.143 hours
Chapter 7 Solutions
OPERATIONS MANAGEMENT W/ CNCT+
Ch. 7.S - Prob. 1DRQCh. 7.S - Prob. 2DRQCh. 7.S - Prob. 3DRQCh. 7.S - Prob. 4DRQCh. 7.S - Prob. 5DRQCh. 7.S - Prob. 6DRQCh. 7.S - Prob. 7DRQCh. 7.S - Prob. 8DRQCh. 7.S - Prob. 9DRQCh. 7.S - Prob. 10DRQ
Ch. 7.S - Prob. 1PCh. 7.S - Prob. 2PCh. 7.S - Prob. 3PCh. 7.S - Prob. 4PCh. 7.S - Prob. 5PCh. 7.S - Prob. 6PCh. 7.S - Prob. 7PCh. 7.S - Prob. 8PCh. 7.S - Prob. 9PCh. 7.S - Prob. 10PCh. 7.S - Prob. 11PCh. 7.S - Prob. 12PCh. 7.S - Prob. 13PCh. 7.S - Prob. 14PCh. 7.S - Prob. 15PCh. 7.S - Prob. 16PCh. 7.S - Prob. 17PCh. 7.S - Prob. 18PCh. 7.S - Prob. 19PCh. 7.S - Prob. 1CQCh. 7.S - Prob. 2CQCh. 7.S - Prob. 3CQCh. 7 - Prob. 1DRQCh. 7 - What are some of the main advantage and...Ch. 7 - Prob. 3DRQCh. 7 - Prob. 4DRQCh. 7 - Prob. 5DRQCh. 7 - Prob. 6DRQCh. 7 - Prob. 7DRQCh. 7 - What are motion study principles? How are they...Ch. 7 - Prob. 9DRQCh. 7 - Prob. 10DRQCh. 7 - Prob. 11DRQCh. 7 - Prob. 12DRQCh. 7 - Prob. 13DRQCh. 7 - Prob. 14DRQCh. 7 - Prob. 15DRQCh. 7 - Prob. 16DRQCh. 7 - Prob. 17DRQCh. 7 - Prob. 18DRQCh. 7 - Prob. 19DRQCh. 7 - Prob. 1TSCh. 7 - Prob. 2TSCh. 7 - Prob. 3TSCh. 7 - Prob. 1CTECh. 7 - Prob. 2CTECh. 7 - Prob. 1PCh. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - Given these observed times (in minutes) for four...Ch. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - Prob. 9PCh. 7 - Prob. 10PCh. 7 - Prob. 11PCh. 7 - Prob. 12PCh. 7 - Prob. 13PCh. 7 - An analyst made the following observations about...Ch. 7 - Prob. 15PCh. 7 - Prob. 16PCh. 7 - Prob. 17PCh. 7 - Prob. 18PCh. 7 - Prob. 19PCh. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQ
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- The product tesla takes 89.88 hours for production of 1 unit, where learning curve rate is 87% and what will be the total time taken by 16th unit of product tesla using incremental unit time method ?arrow_forwardThe first unit of a job took 40 hours to complete. The work has a learning percentage of 88. The manager wants time estimates for units 2, 3, 4, and 5. Develop those time estimates.arrow_forwardBeth Zion Hospital has received initial certification from the state of California to become a center for liver transplants. The hospital, however, must complete its first 18 transplants under great scrutiny and at no cost to the patients. The very first transplant, just completed, required 28 hours. On the basis of research at the hospital, Beth Zion estimates that it will have an 75% learning curve. Using Table E.3, estimate the time it will take to complete: Unit number 5 75% Unit time: .513 Total time: 3.459 80% Unit number 5 Unit time: .596 Total time: 3.738 85% Unit number 5 Unit time: .686 Total time: 4.031 Unit number 18 75% Unit time: .301 Total time: .8.245 Unit number 18 80% Unit time: 3.94 Total Time: 9.716 Unit number 18 85% Unit time: .508 Total time: 11.405 a) the 5th transplant = 14.36 hours b) the first 5 transplant = ? hours (round your response to two decimal places)arrow_forward
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