Chapter 8, Problem 31E

Interpretation Introduction

Interpretation:

For each of the given mass of reactant HgO the mass of product ${\text{O}}_2$ should be determined.

Concept introduction:

When mass of one reactant is given and the mass of product is to be determined, then follow the following solution map:

$\boxed{\text{mass}\text{of}\text{reactant}}\to \boxed{\text{moles of reactant}}\underset{\begin{array}{l}\text{By}\text{using}\\ \text{conversion}\\ \text{factor}\end{array}}{\to }\boxed{\text{moles}\text{of}\text{product}}\to \boxed{\text{mass}\text{of}\text{product}}$

The conversion factor used to convert the moles of reactant into the moles of product is basically the stoichiometric relationship between moles of reactant and moles of product. The conversion factor is obtained from the balanced chemical equation. The mass of reactant or product is converted into their corresponding moles by the use of their corresponding molar masses.

In this given problem, the reactant is $\text{HgO}$ and product is ${\text{O}}_{\text{2}}$. To calculate the mass of oxygen formed in grams by the complete reaction of given mass of $\text{HgO}$, follow the following solution map:

$\boxed{\text{mass}\text{of}\text{HgO}}\to \boxed{\text{moles of HgO}}\underset{\begin{array}{l}\text{By}\text{using}\\ \text{conversion}\\ \text{factor}\end{array}}{\to }\boxed{\text{moles}\text{of}{\text{O}}_2}\to \boxed{\text{mass}\text{of}{\text{O}}_{\text{2}}}$